P27 066

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66. Assuming 

J is directed along the wire (with no radial flow) we integrate, starting with Eq. 27-4,

i =

 

J



 dA =



R

R/2

kr 2πr dr =

2

3



R

3

R

3

8



where k = 3.0

× 10

8

and SI units understood. Therefore, if R = 0.00200 m, we obtain i = 4.40 A.


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