53. We use P
avg
= I
2
rms
R =
12
I
R.
• P
= 0, since R = 0.
=
(0.600 A)
(50 Ω) = 9.0 W.
(0.198 A)
(160 Ω) = 3.14 W.
(0.151 A)
(160 Ω) = 1.82 W.