Zadanie 2b Transformator 24 MVA, 110/30 kV/kV obliczenia na napieciu 30 kV
R/2 X/2 R/2 X/2
U1
B
G
i := i
2 2
30 30
�# ś# �# ś#
R := 1.48�" R = 0.11 X := 21.9�" X = 1.629
ś# ś#
110 110
�# # �# #
2 2
110 110
�# ś# �# ś#
G := 6.6�"10- 6�" B := 61.5�"10- 6�" B = 8.268 � 10- 4
ś# ś#
G = 8.873 � 10- 5
30 30
�# # �# #
U2 := 30�"103
P2 := 19�"106
U2 = 3 � 104
Q2 := 8�"106
S2 := P22 + Q22 S2 = 2.062 � 107
S2
I2 := I2 = 396.746
3�"U2
P2
cosfi2 := cosfi2 = 0.922
S2
I2cz := I2�"cosfi2 I2cz = 365.655
I2b := -sign(Q2) I22 - I2cz2 I2b = -153.96
I2zesp := I2cz + I2b�"i I2zesp = 365.655 - 153.96i
U2zesp := U2
Z2zesp := R + X�"i Z2zesp = 0.11 + 1.629i
UZ2zesp := Z2zesp�"I2zesp UZ2zesp = 291.042 + 578.677i
UZ2 := UZ2zesp
UZ2 = 647.744
UGBzesp := U2zesp + 3�"UZ2zesp UGBzesp = 3.05 � 104 + 1.002i � 103
UGB := UGBzesp
UGB = 3.052 � 104
Yzesp := G - B�"i
Yzesp = 8.873 � 10- 5 - 8.268i � 10- 4
UGBzesp
IYzesp := �"Yzesp
3
IYzesp = 2.041 - 14.51i
I1zesp := I2zesp + IYzesp I1zesp = 367.696 - 168.471i
I1 := I1zesp I1 = 404.454
Z1zesp := R + X�"i Z1zesp = 0.11 + 1.629i
UZ1zesp := I1zesp�"Z1zesp UZ1zesp = 314.903 + 580.404i
U1zesp := UGBzesp + 3�"UZ1zesp
U1zesp = 3.105 � 104 + 2.008i � 103
U1 := U1zesp
U1 = 3.111 � 104
PR1 := 3�"I12�"R
PR1 = 5.402 � 104
QX1 := 3�"I12�"X QX1 = 7.994 � 105
PG := UGB2�"G
PG = 8.266 � 104
QB := UGB2�"B QB = 7.702 � 105
PR2 := 3�"I22�"R PR2 = 5.198 � 104
QX2 := 3�"I22�"X QX2 = 7.692 � 105
P1 := P2 + PR1 + PR2 + PG P1 = 1.919 � 107
Q1 := Q2 + QX1 + QX2 + QB Q1 = 1.034 � 107
P1
cosf1 := cosf1 = 0.88
P12 + Q12
0 + 0i 0 + 0i
�# ś# �# ś#
U2w := U1w :=
ś#U2zesp ś#U1zesp
�# # �# #
�#U1zespś#
UZw :=
ś#U2zesp
�# #
2500
2000
Im(U2w)1500
Im(U1w)
Im(UZw)
1000
500
0
.104 .104 .104 .104 .104 .104
0 5000 1 1.5 2 2.5 3 3.5
Re(U2w) , Re(U1w) , Re(UZw)