59. (a) Since the positron has the same mass as an electron, and the neutrino has negligible mass, then
"mc2 =(mB + me - mC) c2 .
Now, since Carbon has 6 electrons (see Appendix F and/or G) and Boron has 5 electrons, we can
add and subtract 6me to the above expression and obtain
"mc2 =(mB +7me - mC - 6me) c2 =(mB +2me - mC ) c2 .
We note that our final expression for "mc2 involves the atomic masses, as well an extra term
corresponding to two electron masses. From Eq. 38-47 and Table 38-3, we obtain
Q =(mC - mB - 2me) c2 =(mC - mB) c2 - 2(0.511 MeV) .
(b) The disintegration energy for the positron decay of Carbon-11 is
Q =(11.011434 u - 11.009305 u) (931.5MeV/u) - 1.022 MeV = 0.961 MeV .
Wyszukiwarka
Podobne podstrony:
p439p439p439p439p439p4391 9?cquin?81101129081 oeb?9 r1strategia podatkowa wersja skrocona 9p43 8mari?81440608889 oeb?9 r1Cisco 9659więcej podobnych podstron