CIMG0243

Pa = 141.42N Pi3= P32 P32 ~ 141.42N

E P2 = O : P 32 + P 12 = O Pi2= 141.42N Pii=Pn

P21 = 141.42N

I pi i o : | M₂ IP32 h₃₂10

M₂ = P32 h₃₂ = 141.42N*0.298m = 32.50Nm

Rozwiązanie układu sił z uwzględnieniem tarcia.

EP3 = 0 : P^TI3^a+ /^,Ti3^b+ P^T23+ F =0 P^Ti3^a= 1219.57N P^Ti₃^b= 1846.7N

P^Ti3^a = P^T3i^a = 0

P^T3,^a = 1219.57N

?V- P^T3.^b = 0

P^T31^b= 1846.7N P^T23 = 754.21N