Zdjęcie0843

pH = -lg[H+] -»    1.1=-Ig [H*]

[H*| = 0,07943 md/1 ----------------

[H'[ = 10-<-¹

d =

m    100 o __ __ ;n

v = , = —= 97,75 ml **

d 1,0230 g/ml

zdef .% SgllQ\^ 97.75ml x    ml

x = 1,02302 gHCl 36,46 g HG -    1 mol

1,02302 g - x

0,07943 mol H^ł x

1000 ml 430 ml

x = 0,03415 mol IV

x-0,02806 mol H*

(0,02806 mol H^ł + 0,03415 mol 11^f) -    (430 ml + 20 ml)

c    -    1000 ml

c = 0,1382 mol/l

pil =-Ig 0,1382

♦

_PH = 0,86