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VI. Obliczanie średnicy wału:

=818,82 [Mn;	V Mo
A/r2 =4954[Mn] A/r3 M9$4[Mw]	_ /10 81882[/Vcm] ‘^1 ~ V 7500[///cm^2]
kgo =75 MPa	<,2=J^IOW-^2 V
	_ |l0-49540[/Vc/?/] ^ł_\ 7500[W/cm^2]
	^3 i kgo
	_ Jl0-49540[Afo/i] ^5 7500[A'/cm^2]

= 4,8[cw]

= 4 [c/?/]

= 4[cni]

<7, =4,8[c/;/]

cl ₂ = 4 [c/;/]

d₃ = 4[cw]

7