Zdjęcie0258 (9)

Ut=l,90 [m/s]	Ap,=“<v«.r1+A.^i
Pm=1735	^2 i <‘.)
[kg/m^3]	l,9^2*1735,ri+ 42,79^5 [pa]
2,t=0,0263	2 | 0,065j
2s=0,0249	c) Całkowity spadek ciśnienia:
□Lt=42,79 [m]	Ap = Ąps + Ap,
□LS=13,36 [m]	Ąp = 6991,91+57351,91 = 64343,82 [Pa]

Apr=57351,91

[Pal

Ap=64343,82

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