123130

a

<

E

5 )=^_F3 =P y- =*.225kN

F

VF3

6)    Ex,=r + H_D+H_F,+H_A= 0

7)    I^=V,-V_f,=0

8)    J^M_A=-H_D2a-Pa-H_Fia-8 ) => V_F1 = p['J2 -l) = 0.72kN 7)=>V_A=V_Fl= p(V2 -l) = 0.72kN

6) =>H_a =P^~—lj=-0.51WV

Równowaga sił w węźle F:

VF11 | Vf4 Hm*—#*—Hf2

VF3 j ivF2

9)    £x,=-H_F2-H_Fł=0

10)    E^X2=^VF.^+VF4-V^rF2-V„=0

9) =>H_F2=-H_Fł=0

P

10) =>v_F4=v_FI +v_F3-v_FI = ₂ + p^

10 ) => V_F4 =y (3-^/2 (=1.375kN

-p(V2-l)

| Vf*

TF

a

11) £x_I=-v,,₄+v, =0

11)=>V_B =V_F4 =1.375kN

B

a

Vb