3.
*>2 = 46 —
2tt
» — = 439,27 60
Gw = G2 = 34,5[fciV]
P2 = 0,10 * Gw = 0,10 *G2= 3,4S[WV]
C) siły w mechanizmie Pyl = 40,3 [JeiV]
Pxi = 92,0[kN]
d) wypadkowa sił wzbudzających
PyO = Pyt + P2 + P* = 40,3 + 3,45 + 2,3 = 46,05[*JV]
Pro = Pzi + P2 - P6 = 92,0 + 3,45 - 2,3 = 93,15[fcN]
Wymiary fundamentu
a) powienclinw technologię zua
Sy = G1 * 0,8535 + G2 • 1,6085 + G3 * 2,2285 + G4 * 2,6935 + Gs * 3,0835 + +C6 ♦ 3,7735 = 397,501 [klVm]
SM = Gs * 0,35 + G6 « 0,35 = 19,495 A = G2 + G2 + 63 + Gą + (Jg + Gb = 216[kN]
y0=^=0,09[m]
a,*,* = a0 + 2 * 0,40 = 4,98 + 0,80 = 5,78 * 5,80[m] bteeh = bQ + 2 * 0,40 = 2,32 + 0,80 = 3,12 » 3,15[m]
b)
Qtgch
bfsch
b =
* a 3,15 * 7,70
= 4,18 4,20[m]
k ar&ch 5,80
hf = 160 + 15 = 175 [cm] = l,75[m]
, = 95[cm] = 0,95[m] hg = 1,75 -hd = 1,75 - 0,95 - 0,80[m]
Ciężar fundamentu i maszyny „ fkN]
Ybte ~ 25 L3]
Q/d = a*b*hd* ybet = 7,70 * 4,20 - 0,95 « 25 = 768,075[*1V]
Qjg = af-CH * bttch * hg * yb#r = 5,80 * 3,15 * 0,80 * 25 = 365,400[JtcAT] Qf = + Qfg = 1133,475[IcAT]
<?m = .4 = 216[WV]
Qc = Qf + Qm = 1133,475 + 216 - 1349,475[fclV]
Cechy sprężyste podłoża gruntowego
hwl — 1,65 [m] hw2 — 3,10[m] hw3 — 5,00 Tm]
h0 — b — 4,20[m] h'0 = bV2 = 4,20 * V2 = 5,94[m]
ti = hw2 ~bf- l,35[m] £2 = kwa - kw2 — l,90[m]
t3 — h0 — tj —12 — 0,95 [m] t'3 — h'Q — tx — t2 — 2,69[m]
F = a*b = 7,70 * 4,20 = 32,34(m2]
<?c 1349,475
"F “ 7,70 * 4,20
41,73 [fcPa]
2