p14 040

background image

40. Kepler’s law of periods, expressed as a ratio, is



a

M

a

E



3

=



T

M

T

E



2

=

1.52

3

=



T

M

1 y



2

where we have substituted the mean-distance (from Sun) ratio for the semimajor axis ratio. This yields
T

M

= 1.87 y. The value in Appendix C (1.88 y) is quite close, and the small apparent discrepancy is not

significant, since a more precise value for the semimajor axis ratio is a

M

/a

E

= 1.523 which does lead to

T

M

= 1.88 y using Kepler’s law. A question can be raised regarding the use of a ratio of mean distances

for the ratio of semimajor axes, but this requires a more lengthy discussion of what is meant by a “mean
distance” than is appropriate here.


Document Outline


Wyszukiwarka

Podobne podstrony:
p14 040
p14 060
poster 040
P18 040
p14 080
pf 07s038 040
PaVeiTekstB 040
p37 040
C 040
040
p03 040
p14 011
p14 082
p14 065
p14 087
VA 040 Drills, STW
p14 005
mat bud 040 (Kopiowanie) (Kopiowanie)
p14 088

więcej podobnych podstron