75. The uncertainty in the momentum is ∆p = m ∆v = (0.50 kg)(1.0 m/s) = 0.50 kg
·m/s, where ∆v is the
uncertainty in the velocity. Solving the uncertainty relationship ∆x ∆p
≥ ¯h for the minimum uncertainty
in the coordinate x, we obtain
∆x =
¯
h
∆p
=
0.60 J
·s
2π(0.50 kg
·m/s)
= 0.19 m .