p39 071

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71. For U = U

0

, Schr¨

odinger’s equation becomes

d

2

ψ

dx

2

+

8π

2

m

h

2

[E

− U

0

] ψ = 0 .

We substitute ψ = ψ

0

e

ikx

. The second derivative is d

2

ψ/dx

2

=

−k

2

ψ

0

e

ikx

=

−k

2

ψ. The result is

−k

2

ψ +

8π

2

m

h

2

[E

− U

0

] ψ = 0 .

Solving for k, we obtain

k =



8π

2

m

h

2

[E

− U

0

] =

2π

h



2m [E

− U

0

] .


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