p37 048

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48.

(a) We find ∆λ from R = λ/λ = N m:

λ =

λ

N m

=

500 nm

(600/mm)(5.0 mm)(3)

= 0.056 nm = 56 pm .

(b) Since sin θ = m

max

λ/d < 1,

m

max

<

d

λ

=

1

(600/mm)(500

× 10

6

mm)

= 3.3 .

Therefore, m

max

= 3. No higher orders of maxima can be seen.


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