p11 092

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92. We choose

± directions such that the initial angular velocity is ω

0

=

317 rad/s and the values for α,

τ and F are positive.

(a) Combining Eq. 11-12 with Eq. 11-37 and Table 11-2(f) (and using the fact that ω = 0) we arrive

at the expression

τ =



2

5

M R

2

 

ω

0

t



=

2

5

M R

2

ω

0

t

.

With t = 15.5 s, R = 0.226 mand M = 1.65 kg, we obtain τ = 0.689 N

·m.

(b) FromEq. 11-32, we find F = τ /R = 3.05 N.

(c) Using again the expression found in part (a), but this time with R = 0.854 m, we get τ = 9.84 N

·m.

(d) Now, F = τ /R = 11.5 N.


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