p11 058

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58.

(a) The speed of v of the mass m after it has descended d = 50 cm is given by v

2

= 2ad (Eq. 2-16)

where a is calculated as in Sample Problem 11-7 except that here we choose +y downward (so
a > 0). Thus, using g = 980 cm/s

2

, we have

v =

2ad =



2(2mg)d

M + 2m

=



4(50)(980)(50)

400 + 2(50)

= 1.4

× 10

2

cm/s .

(b) The answer is still 1.4

× 10

2

cm/s = 1.4 m/s, since it is independent of R.


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