36.
(a) We interpret the question as asking for N multiplied by the flux through one turn:
Φ
turns
= N Φ
B
= N BA = N B(πr
2
) = (30.0)(2.60
× 10
−3
T)(π)(0.100 m)
2
= 2.45
× 10
−3
Wb .
(b) Eq. 31-35 leads to
L =
N Φ
B
i
=
2.45
× 10
−3
Wb
3.80A
= 6.45
× 10
−4
H .