1.Okreœlenie podstawowych wielkoœci no¿a promieniowego |
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słupkowego. |
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a.największa głębokość zarysu. |
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g=0,5(dmax-dmin)=0.5(25-10)=7,5 |
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wobec tego przyjmujemy następujące wymiary noża: |
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A=19 mm |
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W=75 mm |
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B=6 mm |
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r =0.5 mm |
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C=25mm |
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dr=6 mm |
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D=15 mm |
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M=34,46 |
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wymiary te sprawdzamy wg. zależności : L< 2,5 C |
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L=40 |
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b.wykonawczy kąt natarcia |
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gdzie: |
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c.warunki skrawania : |
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stal o Rm=800-1000MPa |
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twardość HB=235-290 |
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materiał noża SW18 |
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dla tych warunków: |
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Przyjmujemy nastêpuj¹ce wartoœci: |
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d.wymiary charakterystyczne zarysu |
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punkt zarysu |
współrzędne [ mm] |
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li |
ri |
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1 |
0 |
5 |
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2 |
5 |
5,8872 |
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3 |
10 |
7,37965 |
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4 |
15 |
9,5447 |
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5 |
20 |
12,5 |
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6 |
35 |
9 |
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2.Obliczenie rzeczywistego zarysu no¿a (wspó³rzêdnych |
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jego przekroju) |
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odleg³oœæ przed³u¿onej p³aszczyzny natarcia od œrodka przedmiotu |
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Hp= r1*singxu =4.87*sin20 = 1.665639 |
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Punkty |
Promieñ |
K¹tgxu |
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charakter. |
R |
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singxu |
cosgxu |
Hp |
Ei |
Fi |
Gi |
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[mm] |
rad |
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[mm] |
[mm] |
[mm] |
[mm] |
1 |
4,87 |
0,349066 |
0,342020283904747 |
0,939692569619297 |
1,66563878261612 |
4,57630281404598 |
0 |
0 |
2 |
5,7572 |
0,293510152319129 |
0,289314038528472 |
0,957234238371333 |
1,665639 |
5,51098895715144 |
0,934686143105464 |
0,792660583660588 |
3 |
7,24965 |
0,231825326607866 |
0,229754401936645 |
0,973248639757968 |
1,665639 |
6,93961319620873 |
2,36331038216276 |
2,00420536959313 |
4 |
9,4147 |
0,177855151066661 |
0,176918967147121 |
0,984225420858248 |
1,665639 |
9,16284396872934 |
4,58654115468336 |
3,88961622622923 |
5 |
12,37 |
0,135061746615021 |
0,134651495553759 |
0,990893018819457 |
1,665639 |
12,1748684560165 |
7,59856564197056 |
6,44396359267313 |
6 |
8,87 |
0,188904938864733 |
0,187783427282976 |
0,98221045832238 |
1,665639 |
8,78922107692858 |
4,2129182628826 |
3,57276533283759 |
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3.Obliczanie wymiarów no¿a z uwzglêdnieniem tolerancji wykonania |
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a. obliczenie dok³adnej wartoœci promienia zastêpczego |
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Dla danego zakresu œrednic obrabianego materia³u wartoœæ |
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tolerancji wykonania wynosi: IT14 = 0.520 mm |
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W zwi¹zku z tym okreœlamy najwiêkszy promieñ ³uku: |
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r = r5 - 0.25 *IT14 = 12.37 |
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oraz najmniejszy promieñ: |
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rs = r1- 0.25 * IT14 = 4.87 |
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Rozpiêtoœæ 'z' pomiêdzy tymi promieniami wynosi: |
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r |
rs |
rkw |
rskw |
ró¿ [mm] |
z [mm] |
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12,37 |
4,87 |
153,0169 |
23,7169 |
129,3 |
11,3710157857599 |
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obliczamy teraz wartoœæ pomocniczych wspó³czynników k1,k2 : |
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r |
rs |
ró¿ [mm] |
iloc rs |
k1 |
k2 |
x1 |
x2 |
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12,37 |
4,87 |
7,5 |
9,74 |
1,29866666666667 |
1,024 |
7,68 |
6,4068354048 |
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wartoœæ drugiego wspó³czynnika dobieramy z tablic dla gxu=20 |
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W zwi¹zku z powy¿szym, wartoœæ promienia zastêpczego Rzas wynosi: |
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zkw [mm] |
x1 |
x2 |
dzie |
suma |
Rzas |
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129,3 |
7,68 |
6,406835 |
20,1815717120856 |
26,5884067120856 |
13,2942033560428 |
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b.tolerancja ustawienia no¿a |
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Wartoœæ t¹ dobieramy z tablic : Tu = 0.05 mm |
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c.tolerancja wymiarów g³êbokoœciowych narzêdzia |
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Th = (0.3~|0.4 ) * (0.5 *IT14 -Tu) =0.063 mm |
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przyjmujemy: |
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Th = +-0.0367 mm |
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d. tolerancja wymiarów d³ugoœci |
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Tl = (0.6~|0.8)* IT14 = 0.36 mm |
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przyjmujemy |
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Tl =+-0.18 mm |
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e. tolerancja k¹ta: |
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Tgxw = +-15'' |
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wartoœæ t¹ dobraliœmy z tablic |
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f. wymiary poprzeczne no¿a z uwzglêdnieniem tolerancji. |
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riT = ri - 0.25 * IT14 |
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Punkty |
Promieñ |
Wym poprz. |
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charakter. |
R |
RiT |
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[mm] |
[mm] |
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1 |
5 |
4,87 |
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2 |
5,8872 |
5,7572 |
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3 |
7,37965 |
7,24965 |
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4 |
9,5447 |
9,4147 |
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5 |
12,5 |
12,37 |
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6 |
9 |
8,87 |
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LITERATURA: |
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E. Górski,J.Harasymowicz:Podstawy projektowania narzêdzi skrawaj¹cych |
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wraz z zagadnieniami technologicznymi. PWN,W-wa,1980 |
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S. Kunstetter :Narzêdzia skrawaj¹ce do metali - konstrukcja. WNT,W-wa,1970 |
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J. Dietrych, W. Korewa : Podstawy konstrukcji maszyn. t-1 WNT,W-wa,1971 |
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