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10 wybranych wys. Terenu z dokładnością do 1 m |
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mm |
Skala mapy |
1: |
2000 |
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65.2 |
72.4 |
76 |
37.6 |
53.2 |
51.3 |
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mz |
Skala zdjęcia |
1: |
10000 |
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60.1 |
44 |
58.9 |
60.4 |
57.6 |
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p |
pokrycie podłóżne [%] |
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60.00% |
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q |
pokrycie poprzeczne [%] |
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30.00% |
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średnia wys terenu Ht [m] |
58 |
57.8818181818182 |
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l |
format zdjęcia [cm] |
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23 |
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ck |
stała kamery [mm] |
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153 |
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Ho |
wysokość lotniska [m] |
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200 |
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skala mapy topograficznej |
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50000 |
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L |
format teronowy zdjecia [m] |
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2300 |
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Vs |
prędkość samolotu |
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278 |
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Wysokość pikiet |
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0.153 |
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1 |
65.2 |
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2 |
72.4 |
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3 |
76 |
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4 |
37.6 |
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Wysokość lotu nad poziomem lotniska |
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5 |
53.2 |
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6 |
51.3 |
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1. Wysokość lotu nad terenem [m] W = ck * mz |
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7 |
60.1 |
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8 |
44 |
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W= |
1530 |
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9 |
58.9 |
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10 |
60.4 |
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2. bezwzględna wysokośc lotu n.p.m [m] Hb = H + Ht |
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11 |
57.6 |
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Hb = |
1588 |
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3. wysokość lotu nad lotniskiem [m] Hl = Hb – Ho |
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Hl = |
1388 |
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Odstępy między osiami szergów [m] A = l*(1-q)*mz |
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A = |
1610.00 |
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Długość bazy [m] B = l*(1-p)*mz |
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B = |
920.00 |
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Ilość szeregów zdjęć ns = Xc / A + 1 |
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mapa od goscia z naniesionym na zielono zakresem ;) |
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25% szerokości terenowej zdjęcia [m] |
575 |
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Szerokość obszaru [m] |
7000 |
odległość pomierzona na mapie razy skala mapy topograficznej |
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Xc = |
5850 |
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Ilość szeregów ns = |
4.63354037267081 |
5 |
<--zaokrąglasz jeden do góry (musisz wpisać ręcznie) |
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An = |
1463 |
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q = |
36% |
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Ilość zdjęć w szeregach nzi = Si/B + 1 i w całym bloku Nz = suma nzi |
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długość osi szeregu [m] |
5100 |
mierzymy i przeliczamy przez skale tak jak szerokość obszaru |
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nz = |
6.54347826086957 |
14.5555555 |
<--zaokrąglasz jeden do góry (musisz wpisać ręcznie) |
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Nz= |
72.7777775 |
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Długość filmu niezbędnego do wykonania wszystkich zdjęć [m] Lf = 1,1 * Nz *0,26m |
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Lf = |
20.814444365 |
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Powierzchnia stereogramu [ha] Pm = (L – B) * L i powierzchnię użyteczną stereogramu [ha] Ps = A * B |
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Pm = |
317.40000 |
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793500 |
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Ps = |
134.55000 |
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Interwał czasu pomiędzy wykonaniem kolejnych zdjęć [s] t = B / Vs |
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t = |
11.9136690647482 |
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77.2222222222222 |
77222.2222222222 |
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Maksymalny dopuszczalny czas ekspozycji [s] tał = 0,02 mm * mz / Vs |
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tał = |
0.00259 |
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Dokładność a'priori opracowania dwuobrazowego projektowanych zdjęć |
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Mxy = mxy * mz (mxy = +/- 0,02 mm) |
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Mz = +/- W/B * mxy * mz = k * Mxy |
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Mxy = |
0.20 |
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Mz = |
0.33 |
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Nie wiem do ilu miejsc po przecinku mamy podawać wyniki |
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1cm |
500m |
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287.5 |
0.575 |
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0.575 |
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1.606 |
803 |
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1 |
10.5 |
5250 |
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12.1 |
6050 |
14 |
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3 |
13.6 |
6800 |
16 |
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4 |
15.2 |
7600 |
18 |
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15 |
7500 |
18 |
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6 |
13.8 |
6900 |
17 |
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7 |
12.6 |
6300 |
15 |
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8 |
11.3 |
5650 |
14 |
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9 |
10.2 |
5100 |
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138 |
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