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zad MD 2013 I 5
an = 5an-1 - 6an-2 a0 = 2 a1 = 5
bn = 3bn-1 - 2an-2 b0 = 2 b1 = 3
cn = 3cn-1 + 2cn-2 c0 = 2 c1 = 3
Fn n F1 = F2 = 1
Fn = Fn-1 + Fn-2 n > 2
n > 0 F3n
F1 + F3 + F5 + · · · + F2n-1 = F2n
a0 = 3, a1 = 3, an = an-1 + 2an-2.
3
an = 2an-1 - n a0 = 3
bn = bn-1 + 2bn-2 + 3n b0 = 0 b1 = 1
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