Odległość zenitalna (wysokość) ciała z = 90° - h
cos a = cos b cos c + sin b sin c cos A
[a=z b=90°-8 c=90°-cp]
cos(z)=cos(90°~S)cos(90°-cp)+
sin(90°-S)sin(90o-cp)cos(+)
cos(z)=sin(S)sin(cp)+cos(S)cos(cp)cos(t) cos(z)-sin(S)sin(cp)
cos(+)
cos(S)cos(cp)
np. 22.VI. t=6h 5=23°26‘ q)=53026• (Szczecin) cos(z)=0.3977*0.80 31 = 0.3194 z=71°22' => h=18°38'