skanowanie0005 (4)

-= <7,

2

24 ■ /? ■ (T₂    ¹ 24 • /? ■ CTj /J

110² • 0,03492²

24-13,25-10~⁶ -er²

46398,8    _ „„

ct₂--j— = 60,28

= 107,91--

110² - 0,11154²

18,5-10

24-13,25-10"⁶-107,91²    13,25-10

<Ą -60,28-cr₂ -46398,8 = 0

cj₂ » 69,8

'2---->- 2

mm

a := 110

g2 := 0.03492 t2:=0

gl :=0.11154 tl :=-5

crl := 107.91

a := 18.510

a2 :=ol

P := 13.2510 '

Given

: CTl ■

- —(t2-tl)

2 ,2 1

V 24P-cr2^zj

2 .2 a -gl a

24-P-al

a2 :=Find(cr2) o2 = 69.799

f:=

a²g2

8ct2

f = 0.757

Strona 5 z 9