3U]\NáDG:\FLJDQLHGHVNLREFL*RQHMNORFNLHP

.ORFHN  R FL *DU]H

G

 OH*\ QD QLHZD*NLHM GHVFH 'R NORFND SU]\PRFRZDQ\ MHVW SU W 'UXJL

NRQLHF SU WD SRáF]RQ\ MHVW ] SRGSRU QLHSU]HVXZQ 3RPL G]\ GHVN D NORFNLHP L GHVN D

SRGáR*HP PR*H Z\VWSLü WDUFLH :VSyáF]\QQLN WDUFLD QD RE\GZX SRZLHU]FKQLDFK VW\NX

wynosi

µ

ó :\]QDF] PLQLPDOQ VLá  3 SU]\áR*RQ GR GHVNL NWyUD SR]ZROL QD MHM

Z\FLJQL FLHVSRGNORFND

α

=45

0

3

=?



µ

=1/4

*

5R]ZL]DQLH

3U]HGVWDZLP\VLá\G]LDáDMFHQDNORFHNLGHVN 

α

=45

0

3

=?



*

7





7





7





7





1





1





1





1





6

x

y

2

=DSLV]P\UyZQDQLDSU]HGVWDZLDMFHU]XW\QDRVLH[L\VLáG]LDáDMF\FKQDNORFHN

∑

=

⇒

=

S

T

F

x

2

1

0

1

,

∑

−

=

⇒

=

S

G

N

F

y

2

1

0

1

,

VWG

1

1

T

G

N

−

=

.

( 1)

:FKZLOLSRF]WNXUXFKXWDUFLHMHVWZSHáQLUR]ZLQL WHVWDG

1

1

N

T

µ

=

.

( 2)

=UyZQDLRWU]\PXMHP\

)

(

1

1

T

G

T

−

=

µ

,

ZL F

G

T

1

1

+

=

µ

µ

.

( 3)

3U]HMG(P\GRUyZQDUyZQRZDJLGHVNL

5]XWXMFVLá\QDR\RWU]\PDP\

∑

=

⇒

=

2

1

0

N

N

F

y

3RQLHZD*GODWDUFLDZSHáQLUR]ZLQL WHJR

1

1

N

T

µ

=

i

2

2

N

T

µ

=

ZL F

2

1

T

T

=

.

( 4)

=DSLV]P\RVWDWHF]QLHU]XWVLáQDR[

P

T

T

F

x

=

+

⇒

=

∑

2

1

0

.

( 5)

=UyZQDLRWU]\PDP\

G

P

1

2

+

=

µ

µ

3RZVWDZLHQLXZDUWRFL

µ

=¼. mamy

ostatecznie

G

P

5

2

=

v