Oblicz naprężenie gnące wału dane:

Q =1400kG
n = 477,707 min ,

kr

-1

E =2.1·10 MPa = 2.1·10 kG·cm

5

6

-2

l/d= 22,
f= 0,04 mm = 0,004 cm
zakres podkrytyczny => ω

w

< ω

kr

1)

m = Q/g
m = 1,4 [kG·s

2

·cm

-1

]

2)

30

kr

kr

n

⋅

=

π

ω

= 50 [s

-1

]

3)

m

k

kr

=

ω

=>

m

k

kr

⋅

=

2

ω

k = 3500

[kG·cm

-1

]

4)

I =

64

4

d

⋅

π

⎟⎟

⎠

⎞

⎜⎜

⎝

⎛

⋅

⋅

⋅

=

⋅

⋅

=

⋅

⋅

=

⋅

=

3

3

3

4

3

3

4

3

4

3

64

48

48

l

d

d

E

l

d

E

l

d

E

l

I

E

k

π

π

π

4

⎟⎟

⎠

⎞

⎜⎜

⎝

⎛

⋅

⋅

⋅

=

3

3

3

4

d

l

k

E

d

π

Podstawiamy:

22

=

d

l

k = 3500 [kg·s

-2

] E = 2.1·10 [kG·cm ]

6

-2

Otrzymujemy:

( )

53

,

7

22

350000

10

1

,

2

3

4

3

6

=

⋅

⋅

⋅

⋅

=

π

d

5)

2

2

3

3

3

004

,

0

8

22

8

8

32

4

1

32

d

k

d

l

d

f

k

d

l

f

k

d

l

f

k

d

l

P

W

M

x

g

g

π

π

π

π

π

α

ϑ

⋅

⋅

⋅

=

⎟

⎠

⎞

⎜

⎝

⎛

⋅

⋅

=

⋅

⋅

⋅

=

⋅

⋅

⋅

=

⋅

⋅

=

=

83

,

13

7

,

56

3500

224

,

0

224

,

0

2

=

⋅

=

⋅

=

d

k

g

ϑ

[kG·cm

-2

]