p43 055

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55. Let M

Cs

be the mass of one atom of

137

55

Cs and M

Ba

be the mass of one atom of

137

56

Ba. To obtain the

nuclear masses, we must subtract the mass of 55 electrons from M

Cs

and the mass of 56 electrons from

M

Ba

. The energy released is Q = [(M

Cs

55m) (M

Ba

56m) − m] c

2

, where m is the mass of an

electron. Once cancellations have been made, Q = (M

Cs

− M

Ba

)c

2

is obtained. Therefore,

Q = [136.9071 u

136.9058 u] c

2

= (0.0013 u)c

2

= (0.0013 u)(931.5 MeV/u) = 1.21 MeV .


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