p04 045

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45. We apply Eq. 4-32 to solve for speed v and Eq. 4-33 to find the period T .

(a) We obtain

v =

ra =



(5.0 m)(7.0)(9.8 m/s

2

) = 19 m/s .

(b) The time to go around once (the period) is T = 2πr/v = 1.7s. Therefore, in one minute (t = 60 s),

the astronaut executes

t

T

=

60

1.7

= 35

revolutions. Thus, 35 rev/min is needed to produce a centripetal acceleration of 7g when the radius
is 5.0 m.

(c) As noted above, T = 1.7s.


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