p36 036

background image

36. Let the thicknesses (which appear in Fig. 36-31 as different heights h) of the structure be h = kL, where

k is a pure number. In section (b), for example, k = 2. Using Eq. 36-34, the condition for constructive
interference becomes

2h = 2(kL) =

(m + 1/2)λ

n

2

where m = 0, 1, 2, . . .

which leads to

k =

(m + 1/2)λ

2n

2

L

=

(m + 1/2)(600 nm)

2(1.50)(4.00

× 10

3

nm)

=

2m + 1

40

,

or 40k

1 = 2m. This means that 40k − 1 would have to be an even integer. One can check that none of

the given values of k (1, 2,

1
2

, 3,

1

10

) will satisfy this condition. Therefore, none of the sections provides

the right thickness for constructive interference.


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