p43 082

background image

82. The lines that lead toward the lower left are alpha decays, involving an atomic number change of

Z

α

=

2 and a mass number change of ∆A

α

=

4. The short horizontal lines toward the right are

beta decays (involving electrons, not positrons)in which case A stays the same but the change in atomic
number is ∆Z

β

= +1. Fig. 43-16 shows three alpha decays and two beta decays; thus,

Z

f

= Z

i

+ 3∆Z

α

+ 2∆Z

β

and

A

f

= A

i

+ 3∆A

α

.

Referring to Appendix F or G, we find Z

i

= 93 for Neptunium, so Z

f

= 93 + 3(

2)+ 2(1)= 89, which

indicates the element Actinium. We are given A

i

= 237, so A

f

= 237 + 3(

4)= 225. Therefore, the

final isotope is

225

Ac.


Document Outline


Wyszukiwarka

Podobne podstrony:
p08 082
GH 7 082 schemat
p43 069
p43 004
p43 002
Admin 312[01] 01 082
GH 7 082
p43 062
11 2005 077 082
GH 8 082
p14 082
P18 082
GM L1 082
P28 082
Admin 312[01] 02 082
p43 051
p43 054
p43 078

więcej podobnych podstron