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V

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1

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równowagi

M

iA

i

∑

=

0 do obliczenia reakcji V

B

(wybór tego bieguna eliminuje z równania

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równej

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B

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V

B

= ql/4.

Obliczenie V

A

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M

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Trzecie równanie równowagi (np.

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reakcjami H

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nowymi niewiadomymi V

1

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M

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R

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do linii AB) lub

M

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M

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M

iC

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A

2l -H

A

l- H

B

l+Wl/2 = ql/4 2l – 3/4ql l - ql/4 l +ql l/2= 0.

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A

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M

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0 ,

M

iB

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0

P

i

ix

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∑

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B

√

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A

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H

A

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B

√

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R

B

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A

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B

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