I. Zestawienie wyników i parametrów pomiarów |
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Czas [s] |
Kąt skręcenia |
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0 |
17,35 |
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Temperatura: |
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294,7 |
[oC] |
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1590 |
10,54 |
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Masa sacharozy: |
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15,17 |
[g] |
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1890 |
10,17 |
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Stężenie kwasu: |
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2 |
[mol/dm3] |
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2190 |
9,49 |
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2490 |
8,59 |
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2790 |
7,48 |
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3090 |
6,62 |
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3390 |
5,7 |
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3690 |
4,9 |
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3990 |
4,22 |
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4290 |
3,55 |
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4530 |
3,13 |
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5430 |
0,1 |
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5670 |
-0,24 |
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6000 |
-0,65 |
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6300 |
-1,75 |
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6600 |
-2,46 |
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6900 |
-2,98 |
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II. Obliczam stężenie roztworu sacharozy: |
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Korzystam z proporcji w celu obliczenie stężenia |
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w [kg/m3] |
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15,17 |
g = |
0,01517 |
[kg] |
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50 |
cm3 = |
5E-05 |
[m3] |
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Zatem stężenie wynosi |
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5E-05 |
0,01517 |
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1 |
x |
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x = |
303,4 |
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III. Dane potrzebne do sporządzenia wykresu |
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0 |
17,35 |
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1590 |
10,54 |
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1890 |
10,17 |
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2190 |
9,49 |
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2490 |
8,59 |
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2790 |
7,48 |
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3090 |
6,62 |
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3390 |
5,7 |
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3690 |
4,9 |
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3990 |
4,22 |
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4290 |
3,55 |
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4530 |
3,13 |
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5430 |
0,1 |
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5670 |
-0,24 |
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6000 |
-0,65 |
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6300 |
-1,75 |
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6600 |
-2,46 |
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6900 |
-2,98 |
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IV. Obliczenie wartości inf |
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Korzystam ze wzoru: |
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Przy czym skręcalność początkowa wynosi |
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17,35 |
[o] |
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a temperatura: |
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21,7 |
[oC] |
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Stąd po podstawieniu skręcalność końcowa |
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wynosi: |
-5,75 |
[o] |
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V. Przygotowanie danych potrzebnych do wykresu |
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Czas |
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ln |
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0 |
23,10 |
3,14 |
3,13989863266472 |
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1590 |
16,29 |
2,79 |
2,79064503394744 |
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1890 |
15,92 |
2,77 |
2,76767196728581 |
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2190 |
15,24 |
2,72 |
2,72402361086907 |
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2490 |
14,34 |
2,66 |
2,66315917540279 |
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2790 |
13,23 |
2,58 |
2,58260223981353 |
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3090 |
12,37 |
2,52 |
2,51539746093997 |
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3390 |
11,45 |
2,44 |
2,43812290890447 |
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3690 |
10,65 |
2,37 |
2,36570307439263 |
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3990 |
9,97 |
2,30 |
2,29973353115336 |
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4290 |
9,30 |
2,23 |
2,23017836521083 |
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4530 |
8,88 |
2,18 |
2,18397327649368 |
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VI. Obliczenie współczynników A i B gdzie: |
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w punkcjie V i dokonuję regrasji. Uzasadnienie |
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dlaczego odrzuciłem część punktów podam we |
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wnioskach.. |
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xi |
yi |
xi*yi |
xi2 |
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0 |
3,14 |
0,00 |
0 |
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x=czas t |
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1590 |
2,79 |
4437,13 |
2528100 |
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y=ln(at-ainf) |
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1890 |
2,77 |
5230,90 |
3572100 |
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2190 |
2,72 |
5965,61 |
4796100 |
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2490 |
2,66 |
6631,27 |
6200100 |
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2790 |
2,58 |
7205,46 |
7784100 |
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3090 |
2,52 |
7772,58 |
9548100 |
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3390 |
2,44 |
8265,24 |
11492100 |
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3690 |
2,37 |
8729,44 |
13616100 |
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3990 |
2,30 |
9175,94 |
15920100 |
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4290 |
2,23 |
9567,47 |
18404100 |
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4530 |
2,18 |
9893,40 |
20520900 |
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Sumy |
33930,00 |
30,70 |
82874,42 |
114381900,0 |
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Średnie |
2827,50 |
2,56 |
6906,20 |
9531825,00 |
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n = |
12 |
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Współczynnik b: |
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Współczynnik a: |
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b = |
3,16133 |
a = |
-0,00021323 |
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Obliczony współczynnik regresji wynosi : 0,9946 |
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VII. Znając punkty A i B mogę obliczyć teoretyczną skręcalność |
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wynikającą z równań kinetycznych reakcji. W tym celu |
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dokonuję następujących przekształceń. |
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Stąd wynika, że skręcalność początkowa wynosi: |
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17,85 |
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VIII. W oparciu o współczynnik A mogę wyznaczyć stałą |
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k= |
-0,00021 |
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IX. Zestawienie wyników. |
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Wartość skręcalności |
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Doświadczalna |
Teoretyczna |
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17,35 |
17,85 |
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