Project “The development of the didactic potential of Cracow University of Technology in the range of modern
construction” is co-financed by the European Union within the confines of the European Social Fund
and realized under surveillance of Ministry of Science and Higher Education.
Homework 4
Problem 1.
Given the force system shown below:
I. Find the equivalent coupe-force system at point A.
II. Find the equivalent coupe-force system at point B.
III. Find the simplest equivalent force system. Draw the result of reduction on the figure.
2m
3m
1m
2m
2m
2 kN
10 kN
5 kN
kN
kN
kN
A
B
2 kNm
Answers:
I
The equivalent couple-force system at point A consists of a force
)
],
[
2
],
[
2
(
O
kN
kN
S
applied at point A,
and a couple with the moment
])
[
4
,
0
,
0
(
kNm
M
A
II.
The equivalent couple-force system at point A consists of a force
)
],
[
2
],
[
2
(
O
kN
kN
S
applied at point B,
and a couple with the moment
])
[
6
,
0
,
0
(
kNm
M
B
III
. (The origin of a coordinate system is at point A)
The simplest equivalent force system is the resultant force equal
)
],
[
2
],
[
2
(
O
kN
kN
S
acting along the
central axis
]
[
2 m
x
y
Project “The development of the didactic potential of Cracow University of Technology in the range of modern
construction” is co-financed by the European Union within the confines of the European Social Fund
and realized under surveillance of Ministry of Science and Higher Education.
2m
3m
1m
2m
2m
2 kN
10 kN
5 kN
kN
kN
kN
A
B
2 kNm
2m
3m
1m
2m
2m
A
B
y=
-x-
[
2
m
]
W=S(-2[kN ],2[kN ],0)
x
Problem 2.
Reduce the given force system at a point belonging to the central axis (if it’s possible).
he origin of a coordinate system is at point O.
13 kN
6
2 kN
10 kNm
q=4 kN/m
20 kN
4m
3m
5m
=1 kN/m2
45°
O
(
])
[
20
,
0
,
0
(
kNm
M
O
)
T
Project “The development of the didactic potential of Cracow University of Technology in the range of modern
construction” is co-financed by the European Union within the confines of the European Social Fund
and realized under surveillance of Ministry of Science and Higher Education.
Answer:
At an arbitrary point belonging to the central axis described by the equation
]
[
5
4
5
m
x
y
, the force
)
],
[
5
],
[
4
(
O
kN
kN
S
W
system reduces to the resultant force
13 kN
6
2 kN
10 kNm
q=4 kN/m
20 kN
4m
3m
5m
=1 kN/m2
45°
O
4m
3m
5m
O
y=
-5
/4
x+
5[m
]
W=S(4[kN ],-5[kN ],0)
x
y
.