group 1


1) For each grade find number of people who earn salary in this grade.

2) Find people who earn the highest salary for their job and grade.

3) Show names, jobs and hire dates for all people employed in NEW YORK in 1984.

4) Find all employees (personal number, name, profession and salary), who

earn more than the average salary for people with salaries in the second

grade. Display results order by salaries descending.

5) How many people earn more than the minimal salary for the department

located in DALLAS.

6) Find the number of people who don't supervises the others.

7) For each manager find the total monthly income earned by his

subordinates. Display name of manager and the sum.

8) Find all people working as ANALISTS and employed before FORD.

9) Find all jobs which appear in department 10 but not in department 20.

10) For each job in each grade find the minimal yearly income.

Order results by incomes descending.

1) select count(ename),grade from emp,salgrade where sal>=losal and sal<=hisal group by grade;

2) select distinct E1.empno,E1.ename,E1.sal,E1.job from EMP E1, SALGRADE S1

where E1.sal=(select max(E2.sal) from EMP E2

where E1.job=E2.job) order by E1.sal;

3) select ename, job, hiredate from emp e, dept d

where e.deptno=d.deptno and e.hiredate like('1984')

and d.loc='NEW YORK';

4) select empno,ename,job,sal from emp e where e.sal>(select avg(sal) from emp a, salgrade

where grade=2 and a.sal>=losal and a.sal<=hisal) order by sal desc;

5) select count(empno) from EMP where sal>(select min(sal) from EMP where

deptno=(select D.deptno from DEPT D where D.loc='DALLAS'));

6) select count(*) from EMP M

where not exists ( select null from EMP E where E.mgr = M.empno );

7) select A.ename, sum(B.sal) from EMP A, EMP B

where B.mgr=A.empno group by A.ename;

8) select ename from emp where job='ANALYST'

and hiredate < (select hiredate from emp where ename='FORD');

9) select job from emp where deptno=10 MINUS

(select job from EMP where deptno=20) order by job;

10) select min(12*E.sal+NVL(comm,0)),job,grade from EMP E, SALGRADE S where

E.sal between S.losal and S.hisal group by E.job, S.grade

order by min(12*E.sal+NVL(E.comm,0)) desc;



Wyszukiwarka

Podobne podstrony:
Lista odpowiedników FM Group
FEDERICO MAHORA-katalog, PRASA, FM Group
pedagogika Piaget i Wygotski, 2009-2012 (Graduates), GROUP 6, Pedagogika
Golden Delicious Group Payback 2007 12
Grammar Test Group?iE
Group 02 Specifications
group 3
Gale Group Encyclopedia of World Religions Almanac Edition Vol 6
pisanie1 txt, 2009-2012 (Graduates), GROUP 4, PISANIE
E faktura zgoda Flavon Group Polska sp z o o
group 4 PRINT
group 2 PRINT
group 2
81 Group tactics using sweepers and screen player using zon
The Group Souls of Animals
Produkty FM GROUP for home
Posterior Cervical Muscle Group KT method
end-group analysis
CCI Job Interview Workbook 20 w PassItOn and Not For Group Use

więcej podobnych podstron