5

5



RENAL PHYSIOLOGY


Renal Clea


C Ir.ir jih i* primiptr

x    x    x    x    x    x

XXX XX XXX

k    x    x    x    x    x    x    x    .<

X X X .< X X X X X X    X    X    X    X..    X    X    X    X

x x x x x x x|

X    \    XX

{X X X X' x    <    X .X

XXXV X    X    X X

X X X X ,x    x    xx

xxxxxxxxx\xx :<    x    k :<    x    x    x    x    x    x    x x

xxxxxxxxxxx

K    X    X •<    X    X    X    X    X    X    X

X X X X X X X X X





Conrentration

Volume oi

cl substance W

X V

unne per

in uiiutr

ufii time



substance (X) filtered -.hrough glomeruB and not reabsorbed cr

sccrctod by tcbules linulin)

Clearanceot X cciuals glomerular filtration ratę Cs - GFR


$ubstance(X) filtered thrcugh glomerul ar»:l >ecreted bv niaules

fl^ararce of>. equal; glomerular filtration ratę plus tubular set relion ratę C> = CFR + Tx

C» > ^-IISUIIIN


Coicentrjtkn

$ufc$tance(X)


Vo urre ot pląsu 1.1 Uedid of tub>tance(X), pe: unit tinp

(dearćnce ofX)J

Substance {>) filtered througlł glomenilr and reabsorbed by Ubules

Clearance otxoquals glomerular filtration rato minus tubular reabsorplioft rato

C, = GFl-T,

G’x < L*|NUUK


Substance (>.) filtered ihrough glonerjli, reabsrirbsd by tubules, and alfo secreted by tubules

Clcara nc:: ot X equals glomeruUr filtralior ratę

minus nc! reabsorpiion ratę or plus net secretion ratę C, = GFR ±TCx < ur > C Nl,L|N,


.4


U--)

x s I


Figurę 6.5 Renal Clearance


The renal dearance of a substam r pnyides inłormation on how that >ubstancc is handleć by the kidney. l he dea-an. e ol irulin provides a measurc of the GR. II a iiilntaiiLe i*. fretdy filtered at the glomoru-us and its clearanco is less :han that of inulin, the substance if iu.iIi-sorbed hy ihe ne ihrnn Concorsoly, i< the elearanet is greater then


that of inulin then no substance is secreted by the nephron. Figur-6.6 and 6.7 ilustrate ingreate- detail the handling of i suastancc " is leabsorbed (c g-, glucose) and i substance that is secreted «*.i /.wd-dmiro hippurate).



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