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Obliczanie sił wewnętrznych:

PI

7)    = —H_c -R₂ cosa + Ry cosa + H_D =0

8)    JTx₂ ^=vc ^+vd ~2 Q^ + ^|Sina + R₂ sina = 0

9)    Y,^Mc =^VD’l-^pl ^{+ R}? sina /-* q/² =0

(9) => R, =»- ^P—=868N 4 sin a

(8)=*R.= ^P =868N ¹    4 sin a

R,=R₂ =868N

(7)=>H_C=0

(1) =>//_A =0

a-a Ta= 0 N_a=0

M_a =-Pl= -7.755 kNm

Tp =P =1.735 kN N_fl=0

Mp(x_fl)=-P Xp M_p{ 0)=0

M^(/)=-F -/ =-7.755 kNm

r-r

T_Y = —P =-1.735kN N_y =0

My(x_y) =—P • Xy My(0)=0

M_y(/) =-Pl =-7.755kNm &=j8

T_e=0 NS = 0

M_a=-P I =-7.755kNm