2949775112
Solving the integral in I(x) by parts and substituting the resulting expression in (3.15), we get
E[Xl(r,n,m,k)X3 (s,n,m,k)\ — E[Xl{r,n,m,k)X3 (s — l,n,m,k)\
- -r.tr - ms1- r -1)1 r r
x[hm(F(y)) - hm(F(x))]—'-1[F(y)]'" d,ydx
the constant of integration vanishes sińce the integral in I(x) is a definite integral. On using the relation (1.3), we obtain
E[Xl(r, n, m, k)X3(s, n, m, k)] — E[Xl(r, n,m, k)X3 (s — 1 ,n,m, fc)] jaCs.
a/57s(r — l)!(s o/?7s(r — l)!(s — r — 1)!
«Wf(r))-L(W
and hence the result given in (3.14).
Remark 3.2 Setting m = 0, fc = 1 in (3.14), we obtain recurrence relations for product moments of order statistics of the type II exponentiated log-logistic distribution in the form
1 - afln-. +!))*!*•”1 = + af,<Ż-s+l)ElX^]-
Remark 3.3 Putting m = — 1, k > 1 in (3.5), we get the recurrence relations for product moments of upper k records of the type II exponentiated log-logistic distribution in the form
Ratio moments of gos from type II exponentiated log-logistic distribution can be obtain by the following Theorem.
3.5. Theorem. For type II ezponentiated log-logistic distribution as giuen in (1.2)
E[X*(r,n,m,k)Xj ^(s,n,m,k)] = -r—— -r-^-
UU pi9!r(i-p)r(i + i-p)
xn:,(i+!±^)n;,łl(i+“)' fi>3'
Proof From (1.6), we have
E[Xl(r,n,m,k)X3 p (s,n,m,fc)] =
Cs-1
(r — l)!(s — r — l)!(m + l)8-2
X f°° xi[F(x)](’-r+*-°Xm+1)-1f(x)J(x)dx, Jo
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