4H_2(g)+ 10C_(s) = C₁₀H_{8 (s)}

C₁₀H_{8 (s)} + 12 O_{2 (g)} = 10 CO₂ + 4 H₂O _(c) Q_p =

H_2(g) + O_{2 (g)} = H₂O _(c)
= 285,8 kJ/mol

O_{2 (g)} + C_(s) = CO₂
= -393,5 kJ/mol

10 CO₂ + 4 H₂O _(c) = C₁₀H_{8 (s)} + 12 O_{2 (g)} -Q_p= -

4H_2(g) + 2O_{2 (g)} = 4H₂O _(c) 4

10 O_{2 (g)} + 10C_(s) = 10CO₂ 10

Po sumowaniu stronami ostatnich 4 równań otrzymujemy:

4H_2(g)+ 10C_(s) = C₁₀H_{8 (s)}
= 10
+ 4
- Q_p

= 10
+ 4
- Q_p

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