p11 082

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82. We make use of Table 11-2(e) as well as the parallel-axis theorem, Eq. 11-27, where needed. We use 

(as a subscript) to refer to the long rodands to refer to the short rod.

(a) The rotational inertia is

I = I

s

+ I



=

1

12

m

s

L

2
s

+

1

3

m



L

2


= 0.019 kg

·m

2

.

(b) We note that the center of the short rodis a distance of h = 0.25 m from the axis. The rotational

inertia is

I = I

s

+ I



=

1

12

m

s

L

2
s

+ m

s

h

2

+

1

12

m



L

2


which again yields I = 0.019 kg

·m

2

.


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