METODA ŚREDNIEJ SZEROKOŚCI - I PROBLEM ŻEGLUGI PO LOKSODROMIE |
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DANE |
jA |
lA |
KDd |
d [Mm] |
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UWAGA ! |
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[ o ] |
67 |
89 |
073° |
438,4 |
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Stosując metodę średniej szerokości , trzeba pamiętać , że : |
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[ ' ] |
55 |
31 |
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a) szerokości geograficzne nie powinny przekraczać 60o , |
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znak |
S |
E |
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b) różnica szerokości mniejsza od 5 stopni lub droga po loksodromie mniejsza niż 600 Mm , |
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c) loksodroma nie może przecinać równika , |
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jA |
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lA |
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KDd |
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d) najlepiej , gdy KDd jest zbliżone do 90 i 270 stopni . |
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-67,917° |
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89,517° |
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N |
73° |
E |
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1.Obliczanie różnicy szerokości - Dj: |
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Dj = d * cos KDd |
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Dj = |
128,520' |
Dj = |
2,142° |
Dj = |
02° 08,5' |
N |
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2. Obliczanie średniej szerokości - jśr : |
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jśr = jA + Dj/2 |
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Dj/2 = |
1,071° |
Dj/2 = |
01° 04,3' |
N |
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jśr = |
-66,846° |
jśr = |
66° 50,7' |
N |
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3. Obliczanie zboczenia nawigacyjnego - a: |
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a = d * sin KDd |
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a = |
419,139 |
Nm (E) |
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4. Obliczanie różnicy długości - Dl: |
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Dl = a * sec jśr |
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Dl = |
1065,944' |
Dl = |
17,766° |
Dl = |
017° 45,9' |
E |
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5. Obliczanie współrzędnych punktu B - (jB , lB): |
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jB = jA + Dj lB = lA + Dl |
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jB = |
-65,775° |
jB = |
65° 46,5' |
S |
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lB= |
107,282° |
lB= |
107° 16,9' |
E |
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METODA ŚREDNIEJ SZEROKOŚCI - II PROBLEM ŻEGLUGI PO LOKSODROMIE |
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DANE |
jA |
lA |
jB |
lB |
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UWAGA ! |
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[ o ] |
45 |
21 |
56 |
78 |
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Stosując metodę średniej szerokości , trzeba pamiętać , że : |
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[ ' ] |
2,9 |
34,9 |
11,4 |
14,1 |
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a) szerokości geograficzne nie powinny przekraczać 60o , |
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znak |
N |
E |
N |
W |
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b) różnica szerokości mniejsza od 5 stopni lub droga po loksodromie mniejsza niż 600 Mm , |
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c) loksodroma nie może przecinać równika . |
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jA= |
45,048° |
lA= |
21,582° |
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jB= |
56,190° |
lB= |
-78,235° |
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1. Obliczanie różnicy szerkości i różnicy długości: Dj , Dl |
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Dj = jB - jA Dl = lB - lA |
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Dj = |
11,142° |
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Dl = |
-99,817° |
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Dj = |
668,5' |
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Dl = |
-5989,0' |
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Dj = |
11° 08,5' |
N |
Dl = |
099° 49,0' |
W |
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2. Obliczanie średniej szerokości - jśr : |
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jśr = jA + Dj/2 |
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Dj/2 = |
5,571° |
Dj/2 = |
05° 34,3' |
N |
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jśr = |
50,619° |
jśr = |
50° 37,1' |
N |
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3. Obliczanie zboczenia nawigacyjnego - a: |
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a = Dl * cosjśr |
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a = |
3799,879 |
Mm (W) |
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4. Obliczanie kąta drogi nad dnem (kursu) - KDd: |
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tan KDd = a / Dj |
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tan KDd = |
5,68402 |
KDd = |
N |
80,022° |
W |
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KDd = |
280,0° |
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5. Obliczanie drogi po loksodromie - d: |
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d = Dj * secKDd |
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d = |
3858,26 |
Mm |
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METODA POWIĘKSZONEJ SZEROKOŚCI - I PROBLEM ŻEGLUGI PO LOKSODROMIE |
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Dane |
jA |
lA |
KDd |
d [Mm] |
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UWAGA ! |
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[ o ] |
52 |
160 |
056° |
5650,0 |
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Metodę powiększonej szerokości można stosować zawsze , a w szczególności w : |
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[ ' ] |
30 |
45 |
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a) przy żegludze w szerokościach ponad 60 stopni , |
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znak |
S |
W |
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b) gdy różnica szerokości jest większa od 5 stopni . |
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jA |
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lA |
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KDd |
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-52,500° |
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-160,750° |
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N |
56° |
E |
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1.Obliczanie różnicy szerokości - Dj: |
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Dj = d * cos KDd |
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Dj = |
3159,440' |
Dj = |
52,657° |
Dj = |
52° 39,4' |
N |
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2. Obliczanie szerokości punktu B - jB: |
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jB = jA + Dj |
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jB = |
0,157° |
jB = |
00° 09,4' |
N |
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3. Obliczanie różnicy powiększonej szerokości - DV: |
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DV =|VB - VA| |
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VB = |
0009,4 |
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- VA = |
-3695,9 |
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DV = |
3705,3 |
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|DV | = |
3705,3 |
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4. Obliczanie różnicy długości - Dl: |
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Dl = DV * tgKDd |
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Dl = |
5493,293' |
Dl = |
91,555° |
Dl = |
091° 33,3' |
E |
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5. Obliczanie długości punktu B - lB: |
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lB = lA + Dl |
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lB= |
-69,195° |
lB= |
069° 11,7' |
W |
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METODA POWIĘKSZONEJ SZEROKOŚCI - II PROBLEM ŻEGLUGI PO LOKSODROMIE |
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DANE |
jA |
lA |
jB |
lB |
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UWAGA ! |
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[ o ] |
44 |
8 |
25 |
77 |
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Metodę powiększonej szerokości można stosować zawsze , a w szczególności w : |
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[ ' ] |
57 |
47 |
34 |
1 |
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a) przy żegludze w szerokościach ponad 60 stopni , |
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znak |
S |
w |
N |
W |
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b) gdy różnica szerokości jest większa od 5 stopni . |
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jA= |
-44,950° |
lA= |
-8,783° |
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jB= |
25,567° |
lB= |
-77,017° |
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1. Obliczanie różnicy szerkości i różnicy długości: Dj , Dl |
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Dj = jB - jA Dl = lB - lA |
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Dj = |
70,517° |
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Dl = |
-68,234° |
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Dj = |
4231,0' |
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Dl = |
-4094,0' |
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Dj = |
70° 31,0' |
N |
Dl = |
068° 14,0' |
W |
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2. Obliczanie różnicy powiększonej szerokości - DV: |
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DV =|VB - VA| |
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VB = |
1577,7 |
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- VA = |
-3009,4 |
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DV = |
4587,1 |
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|DV | = |
4587,1 |
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3. Obliczanie kąta drogi nad dnem (kursu) - KDd: |
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tan KDd = Dl / DV |
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tan KDd = |
0,892509857515921 |
KDd = |
N |
41,749° |
W |
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KDd = |
318,3° |
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4. Obliczanie drogi po loksodromie - d: |
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d = Dj * secKDd |
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d = |
5671,08 |
Mm |
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