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ROZPIĘTOŚĆ |
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L= |
14.50 |
m |
14500 |
mm |
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XXXXX |
komórki które trzeba zedytować |
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WYSOKOŚĆ |
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h/l=1/ |
3 |
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XXXXX |
komórki które mogą być te same |
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H= |
4.83 |
m |
4833.33333333333 |
mm |
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ROZSTYAW DZWIGARÓW |
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a= |
1.20 |
m |
1200 |
mm |
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DREWNO LITE KL C |
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30 |
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POKRYCIE DACZU |
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gont bitumiczny |
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BUDYNEK O WYMIARACH |
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OBC. ŚNIEGIEM |
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2 |
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OBC. WIATREM |
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2 |
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1.0 |
Geometria |
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tg α = |
0.67 |
=> |
α = |
33.6900675259798 |
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cos α = |
0.832 |
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sin α = |
0.555 |
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L1 = |
4356.70779118565 |
mm |
4.357 |
m |
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L2= |
2904.47186079043 |
mm |
2.904 |
m |
Przyjęto |
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pas górny |
80 |
x |
190 |
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L3= |
5236.11111111111 |
mm |
5.236 |
m |
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pas dolny |
80 |
x |
150 |
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L4= |
5236.11111111111 |
mm |
5.236 |
m |
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krzyżulec |
70 |
x |
80 |
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L5= |
4027.77777777778 |
mm |
4.028 |
m |
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2.0 Zestawienie obciążeń |
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2.1 Stałe dachu |
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γf |
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dachówka ceramiczna |
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0.460 |
1.2 |
0.552 |
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zabaczyć w notatkach i rozbić łaty i folię |
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łaty + folia |
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0.065 |
1.2 |
0.078 |
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q1k= |
0.710 |
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q1d= |
0.852 |
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2.2 Stałe stropu podwieszonego (pasa dolnego) |
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γf |
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Płyta GKF 12,5mm |
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0.150 |
1.2 |
0.180 |
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listwy 0,06*0,032*6 |
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0.031 |
1.1 |
0.034 |
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Folia aluminiowa |
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0.015 |
1.2 |
0.018 |
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Wełna mineralna 15cm |
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0.150 |
1.2 |
0.180 |
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q2k= |
0.340 |
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q2d= |
0.410 |
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2.3 Ciężar własny dachu |
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γf |
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g3kd= |
0.014 |
*L= |
0.203 |
1.1 |
0.223 |
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2.4 Obciążenie śniegiem |
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s=qk*C |
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γf |
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C=0,8+0,4*(α-15)/15 |
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0.947 |
1.4 |
1.326 |
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2.5 Obciążenie wiatrem |
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I wariant |
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q1= |
0.35 |
II strefa |
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Ce= |
1 |
teren A |
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β= |
1.8 |
bud niepodpiwniczony |
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C2(n)=0,015*α-0,2= |
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0.305351012889697 |
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C2(z)= |
-0.4 |
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qk |
γf |
qd |
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nawietrana |
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W1kd= |
q1*Ce*β*C2= |
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0.192 |
1.3 |
0.250 |
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zawietrzna |
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W2kd= |
q1*Ce*β*C2= |
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-0.252 |
1.3 |
-0.328 |
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II wariant |
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C2'= -0,045*(40-α) = |
-0.28394696133091 |
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qk |
γf |
qd |
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W1kd'= |
q1*Ce*β*C2'= |
-0.179 |
1.3 |
-0.233 |
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W2kd'= |
q1*Ce*β*C2= |
-0.252 |
1.3 |
-0.328 |
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3.0 Obliczenia sił obciążeń w węzłach kratownicy |
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3.1 Od obciążeń stałych i śniegu |
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0,5 g3 |
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a) pasa górnego |
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P1k(g1)= |
3.712 |
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P1k(g3)= |
0.442 |
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P1k(s)= |
4.119 |
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P1d(g1)= |
4.454 |
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P1d(g3)= |
0.971 |
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P1d(s)= |
5.767 |
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całkowite obciążenie w węźle pasa górnego |
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P1k= |
8.273 |
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P1d= |
11.19 |
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b) pasa dolnego |
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P2k(g2)= |
1.890 |
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P2k(g3)= |
0.564 |
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P2d(g2)= |
2.279 |
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P2d(g3)= |
0.621 |
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całkowite obciążenie w węźle pasa dolnego |
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P2k= |
2.454 |
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P2d= |
2.900 |
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3.2 Obciążenie skupione od wiatru |
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I wariant |
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W1k= |
0.905 |
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W2k= |
-1.19 |
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II wariant |
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W1k'= |
-0.84 |
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W2k'= |
-1.19 |
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W1d= |
1.177 |
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W2d= |
-1.54 |
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W1d'= |
-1.09 |
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W2d'= |
-1.54 |
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4.0 Siły wewnętrzne w prętach układu |
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4.1 Siły Mi1 od obciążeń jednostkowych węzłów |
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1 |
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2 |
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3 |
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4 |
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SIŁY |
Obciążenie jednostkowe węzłów |
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P1=1 |
P2=1 |
W1=1 |
W2=1 |
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1 |
G1 |
-2.70 |
-1.80 |
-1.18 |
-1.08 |
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2 |
G2 |
-2.13 |
-1.80 |
-1.18 |
-1.08 |
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3 |
G1' |
-2.70 |
-1.80 |
-1.08 |
-1.18 |
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4 |
G2' |
-2.13 |
-1.80 |
-1.08 |
-1.18 |
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5 |
D1 |
2.24 |
1.50 |
0.70 |
0.90 |
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6 |
D2 |
1.49 |
1.07 |
-0.20 |
0.90 |
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7 |
D1' |
2.24 |
1.50 |
-0.20 |
1.80 |
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8 |
K1 |
-0.84 |
0.00 |
-1.00 |
0.00 |
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9 |
K1' |
-0.84 |
0.00 |
0.00 |
-1.00 |
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10 |
K2 |
0.75 |
1.10 |
0.90 |
0.00 |
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11 |
K2' |
0.75 |
1.10 |
0.00 |
0.90 |
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4.2 Siły wewmętrzne w prętach kratownicy |
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Siły |
Obciążenia węzłów obliczeniowych |
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P1d= |
11.19 |
P2d= |
2.900 |
W1d |
W2d |
Ekstr |
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G1, G1' |
-30.221 |
-5.219 |
-1.39 |
1.66 |
-36.828 |
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G2, G2' |
-23.841 |
-5.219 |
-1.39 |
1.66 |
-29.060 |
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D1, D1' |
25.072 |
4.349 |
1.18 |
1.82 |
29.421 |
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D2 |
16.677 |
3.102 |
1.18 |
1.82 |
19.780 |
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K1, K1' |
-9.402 |
0.000 |
0.82 |
-1.39 |
-8.578 |
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K2, K2' |
8.395 |
3.189 |
0.22 |
-1.39 |
11.803 |
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4.3 Momenty zginające pasa górnego |
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3.334 |
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4.449 |
KNm |
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-7.911 |
KNm |
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4.4 Wymiarowanie prętów układu |
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Stan graniczny nośności nad podporą da się określić według zależności: |
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Wytrzymałości obliczeniowe materiału |
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-drewno kl C |
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30 |
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- charakterystyczne |
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fmk= |
30 |
MPa |
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fcok= |
23 |
MPa |
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ft0k= |
18 |
MPa |
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Eo,mean= |
12000 |
MPa |
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E0.05= |
8000 |
MPa |
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ρmean= |
460 |
kg/m3 |
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ρk= |
380 |
kg/m3 |
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kmod= |
klasa użytkowania 2 |
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klasa trwania obciążenia |
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stałe |
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śnieg - średniotrwałe |
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wiatr - krótkotrwałe |
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materiał - drewno lite |
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- drewno lite |
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γm= |
1.3 |
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kmod= |
0.9 |
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βc= |
0.2 |
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f cod= |
15.9230769230769 |
MPa |
na ściskanie |
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f tod= |
12.46 |
MPa |
na rozciąganie |
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f myd= |
20.77 |
MPa |
w obu kierunkach |
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Parametry przekroju |
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pas górny |
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80 |
x |
190 |
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pole powierzchni przekroju Ad= |
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15200 |
mm2 |
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Wy= |
481.333333333333 |
x10^3 mm3 |
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Jy= |
54.91 |
mm |
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4357 |
mm |
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Jz= |
23.12 |
mm |
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smukłość |
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79.3 |
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4.5 Nośność pasa górnego |
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Nad podporą Kcy=1 |
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2.42 |
N/mm2 => |
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2.42 |
Mpa |
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16.44 |
Mpa |
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0.815 |
< 1 |
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waunek spełniony |
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. |
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W przęśle |
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12.53 |
Mpa |
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1.503 |
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1.355 |
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0.464 |
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2.42 |
N/mm2 => |
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2.42 |
Mpa |
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9.24 |
Mpa |
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0.773 |
< 1 |
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waunek spełniony |
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. |
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4.6 Nośność pasa dolnego |
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5236 |
4028 |
5236 |
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1 |
0.77 |
1 |
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0.626 |
kN/m |
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α1= |
0.09 |
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źle |
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αp= |
-0.09 |
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źle |
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Dla |
1 |
0.77 |
1 |
przyjęto 1 |
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0.80 |
1 |
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α2= |
-0.01 |
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źle |
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1.4691 |
kNm |
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-0.1013 |
kNm |
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-1.4743 |
kNm |
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Warunek nośności |
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Pas dolny przyjęto |
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80 |
150 |
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Anet= |
12000 |
mm2 |
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σ tod= |
2.452 |
N/mm2 |
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Wn= |
300.0 |
x10^3mm3 |
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σ myd= |
4.91 |
N/mm3 |
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D1d= |
29.42 |
kN |
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Mpd= |
-1.47 |
kNm |
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Za duży zapas. Zredukować przekrój belki, w poz.1.0. |
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0.433 |
< 1 |
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waunek spełniony |
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. |
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4.7 Nośność krzyżulca |
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Przyjęto przekrój krzyżulca |
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b= |
70 |
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h= |
80 |
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Ad=b*h= |
5600 |
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f cod= |
15.9230769230769 |
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βc= |
0.2 |
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i=0,289*b= |
20.23 |
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λ cz=L2/i= |
143.6 |
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0.155 |
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2.452 |
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3.83 |
Mpa |
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3.700 |
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1.53 |
Mpa |
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0.623 |
< 1 |
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waunek spełniony |
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. |
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5.0 Złącza na płytki kolczaste |
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WĘZEŁ A |
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a= |
228.35 |
> B |
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L1= |
342.53 |
> L |
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Przyjmuję płytkę M16 |
B= |
229 |
|
L= |
305 |
(tab. 7-2) |
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F1 = |
100 |
N/cm2 - nośność obliczeniowa płytek typu M16 z uwagi na docisk |
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kloców do drewna (z tab. 7-9 β=0 i α= |
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33.6900675259798 |
) |
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Wymagana powierzchnia docisku kolców do otaczającego drewna . |
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Pas górny |
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Pas dolny |
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η= |
0.65 |
(tab 7.12) |
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η= |
0.8 |
(tab 7-12) |
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283.30 |
cm2 |
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183.883218108665 |
cm2 |
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Rzeczywiste powierzchnie netto płytki |
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Pas górny |
|
A g net= B' *L' *0,5 |
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L1= |
342.5 |
mm |
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B'=B-10= |
209 |
mm |
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L'=L-10= |
285 |
mm |
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A g net= |
297.825 |
cm2 > |
283.30 |
cm2 |
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|
waunek spełniony |
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. |
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Pas dolny |
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L2= |
225.0 |
mm |
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B'= |
130 |
mm |
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L'= |
215.0 |
mm |
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A d net= |
230.75 |
cm2 > |
183.88 |
cm2 |
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|
waunek spełniony |
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. |
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Ostatecznie przyjęto płytkę M16 |
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229 |
305
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mm |
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Scinanie |
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|
446.041906762912 |
N/cm |
|
412.8 |
mm |
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α = |
30 |
F1v = |
535 |
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α = |
33.6900675259798 |
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F1v = |
567 |
> Fv= |
446 |
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α = |
45 |
F1v = |
665 |
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waunek spełniony |
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(z tabeli 7-11 z interpolacji liniowej) |
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. |
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WĘZEŁ B |
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- Pas górny |
|
PIId = G1d - G2d = |
7.768 |
kN |
bk= |
80 |
mm |
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P1d= |
11.19 |
kN |
l1= |
185 |
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P1┴ = |
9.313 |
kN |
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tg α = |
0.834147283644889 |
=> α= |
39.83 |
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12.13 |
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tg β = |
1.19882905526036 |
=> β= |
50.17 |
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Przyjęto szerokość płytki M16 B= |
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|
76 |
(tab 7-2) |
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β = |
45 |
F1 = |
77 |
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β = |
50.17 |
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F1v = |
75 |
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β = |
60 |
F1 = |
70 |
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(z tabeli 7-9 z interpolacji liniowej) |
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- Wymagana powierzchnia płytki |
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81.30 |
cm2 |
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Rzeczywista powierzchnia |
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A g net = |
99.00 |
> |
81.30 |
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|
waunek spełniony |
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. |
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- Krzyżulec |
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K1d= |
8.58 |
kN |
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42.89 |
cm2 |
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F1k1= |
100 |
N/cm2 - nośność obliczeniowa płytek typu M16 z uwagi na docisk |
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kloców do drewna (z tab. 7-9 β=0 i α=0 |
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interpolowana liniowo) |
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według tab 7-2 przyjmuję długość L= |
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305 |
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L1= |
185 |
mm |
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L2= |
120 |
mm |
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A k net = (bk-20)*(L1-20) |
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A k net = |
60.00 |
>
|
42.89 |
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|
waunek spełniony |
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- Ścięcie płytki |
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Nośność obliczeniowa płytek typu M16 na ścinanie F1v [N/cm] z tablicy 7-11 dla: |
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α = |
90 |
F1v = |
570 |
N/cm |
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|
736.373884586067 |
N/cm |
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lv = |
76.0 |
mm |
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F1v = |
570 |
> Fv= |
736.4 |
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. |
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warunek nie spełniony |
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Ostatecznie przyjęto płytkę M16 |
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|
76 |
305 |
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WĘZEŁ D |
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D II= d1d - D2d = |
9.641 |
kN |
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D┴ =P2d = |
2.900 |
kN |
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|
10.07 |
kN |
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Przyjęto płytki M16 o wymiarach |
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|
152
|
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|
- Zakotwienie płytki w pasie dolnym |
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0.30 |
=> β = |
16.74 |
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F1d = |
92 |
N/cm2 - nośność obliczeniowa płytek typu M16 z uwagi na docisk |
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kloców do drewna (z tab. 7-9 β=15 i α=15) |
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54.72 |
cm2 |
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8.58 |
kN |
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44.5720166206837 |
cm2 |
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F1k1= |
96 |
N/cm2 - nośność obliczeniowa płytek typu M16 z uwagi na docisk |
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α = |
45 |
F1 = |
100 |
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kloców do drewna (z tab. 7-9 β=0 i α=90- |
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|
33.6900675259798
|
interpolowana liniowo) |
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α = |
56.31 |
|
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F1v = |
96 |
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α = |
60 |
F1 = |
95 |
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|
- Zakotwienie płytki w krzyżulcu K2 = |
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11.80 |
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(z tabeli 7-9 z interpolacji liniowej) |
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69.2988821700424 |
cm2 |
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|
arc tg |
2.4 |
=> |
67.3801350519596 |
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F2k= |
85 |
N/cm2 - nośność obliczeniowa płytek typu M16 z uwagi na docisk |
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α = |
60 |
F1 = |
95 |
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|
kloców do drewna (z tab. 7-9 β=0 i α= |
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|
67.4 |
interpolowana liniowo) |
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α = |
67.38 |
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F1v = |
85 |
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α = |
75 |
F1 = |
75 |
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|
Sprawdzenie powierzchni efektywnych: |
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|
αk1 = |
56.3099324740202 |
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|
(z tabeli 7-9 z interpolacji liniowej) |
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Ak1n= |
47.6 |
> |
Ak1 = |
44.57 |
sin |
56.3099324740202 |
=> |
0.832 |
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Ak2n= |
42.9 |
> |
Ak1 = |
69.30 |
sin |
67.3801350519596 |
=> |
0.923 |
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Adn= |
201.3 |
> |
Ak2 = |
54.72 |
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- ścięcie płytek |
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lv = |
305
|
cm |
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F1v = |
450 |
N/cm odczytana z tab 7-11 dla α=0 i M16 |
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V = DII = |
9.641 |
kN |
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158.1 |
< |
450 |
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|
waunek spełniony |
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. |
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Ostatecznie przyjęto w węźle D płytkę 2xM16 o wymiarach |
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|
152
|
305 |
mm |
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|
WĘZEŁ C |
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|
- Zakotwienie płytki w pasie górnym ze względu na siłę P1d. |
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F1 = |
58 |
N/cm2 - nośność obliczeniowa płytek typu M16 z uwagi na docisk |
|
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β = |
30 |
F1 = |
58 |
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|
kloców do drewna (z tab. 7-9 β= |
|
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|
|
33.6900675259798 |
i α=90 interpolowana liniowo) |
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β = |
33.69 |
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F1v = |
58 |
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β = |
45 |
F1 = |
57 |
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|
Przyjęto płytki M16 o szerokości B= |
|
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|
114 |
mm i długości L= |
|
|
203 |
mm |
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|
(z tabeli 7-9 z interpolacji liniowej) |
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|
0,55*B < 0,5*L |
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62.7 |
mm < |
|
101.5 |
mm |
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|
P1d = |
11.19 |
kN |
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48.45 |
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Apn = |
60.078 |
> |
48.45 |
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|
waunek spełniony |
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. |
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|
- Ścięcie płytki |
|
|
lv = |
114.0 |
mm |
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|
Nośność obliczeniowa płytek typu M16 na ścinanie F1v [N/cm] z tablicy 7-11 dla: |
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α = |
90 |
F1v = |
570 |
N/cm |
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|
490.9 |
N/cm |
F1v > Fv |
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|
570 |
> |
490.9 |
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|
|
waunek spełniony |
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. |
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Ostatecznie przyjęto w węźle C płytkę 2xM16 o wymiarach |
|
|
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|
|
114
|
203 |
mm |
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|
- Zakotwienie płytki dolnej w krzyżulcu K2 |
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|
Przyjęto płytki M16 o wymiarach |
|
|
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|
171
|
mm |
|
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|
K2d = |
11.80 |
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|
69.30 |
cm2 |
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F1 = |
85 |
N/cm2 - nośność obliczeniowa płytek typu M16 z uwagi na docisk |
|
|
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|
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|
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|
|
α = |
60 |
F1 = |
95 |
|
|
|
|
kloców do drewna (z tab. 7-9 β=0 i α= |
|
|
|
|
|
67.4 |
interpolowana liniowo) |
|
|
|
|
|
α = |
67.38 |
|
|
F1v = |
85 |
|
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|
|
α = |
75 |
F1 = |
75 |
|
|
- Zakotwienie płytki dolnej w pasie górnym |
|
|
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|
|
|
|
(z tabeli 7-9 z interpolacji liniowej) |
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|
|
K2d = |
11.80 |
|
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|
φ1 = φk2 - φG = |
33.7 |
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|
G2d-1= K2d *cosφ1 = |
10 |
kN |
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|
|
49.10 |
cm3 |
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|
|
F1 = |
100 |
N/cm2 - nośność obliczeniowa płytek typu M16 z uwagi na docisk |
|
|
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|
|
|
kloców do drewna (z tab. 7-9 β=0 i α= |
|
|
|
|
|
33.6900675259798 |
) |
|
|
|
|
|
|
|
|
|
|
|
|
Przyjęto płytki M16 o wymiarach |
|
|
|
|
171 |
407 |
mm |
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|
Sprawdzenie powierzchni efektywnych: |
|
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|
|
10.6 |
|
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|
|
Ag2n = |
92.88 |
> Ag2= |
|
49.10 |
cm3 |
|
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|
waunek spełniony |
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. |
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|
Ak2n = |
67.58 |
> Ak2= |
|
69.30 |
cm2 |
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warunek nie spełniony |
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- sprawdzenie wytrzymałości płytki na ścinanie |
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lv = 0,5*L/cosα = |
24.46 |
cm |
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Nośność obliczeniowa płytek typu M16 na ścinanie F1v [N/cm] z tablicy 7-11 dla: |
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α = |
33.6900675259798 |
F1v = |
567 |
N/cm |
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β = |
30 |
F1 = |
535 |
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200.8 |
N/cm |
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β = |
33.70 |
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F1v = |
567 |
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β = |
45 |
F1 = |
665 |
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(z tabeli 7-11) |
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F1v > Fv |
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567.066666666667 |
> |
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200.8 |
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waunek spełniony |
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. |
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Ostatecznie przyjęto w węźle C płytkę 2xM16 o wymiarach |
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171
|
407 |
mm |
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6.0 Połączenie pasa dolnego na długości |
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Połączenie przyjęto w punkcie przęsła środkowego gdzie nie występuje moment zginający, |
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w odległości od węzła D wynoszącej: |
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le = 0,2*l= |
805.555555555556 |
mm |
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W punkcie E działa siła podłużna rozciągająca Nd2= |
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19.78 |
kN oraz obciążenie pasa: |
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qd = |
0.6285 |
kN/m |
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0.7594375 |
kN |
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Me = 0 |
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Przyjęto płytki M16 o szerokości |
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76 |
mm |
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. |
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Wypadkowa |
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Wd = |
19.7944393742974 |
kN |
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Potrzedna powierzchnia płytki M16 (dla β=0, F1= |
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100 |
N/cm2 ) |
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arc tgε = |
0.038394472123056 |
=> ε= |
2.19876120969638 |
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An = |
98.972196871487 |
cm2 |
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Potrzebna długość płytki: |
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lp > An/b = |
13.0226574830904 |
cm |
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0,55*b= |
41.8 |
< |
130.226574830904 |
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warunek producenta nie został spełniony |
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Zastosowano połączenia na gwoździe jednocięte |
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Zastosowano nakładki grubości |
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25 |
mm i gwoździe jednocięte |
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d= |
3.5
|
90 |
mm |
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Obliczenie nośności gwoździ na 1 cięcie: |
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t1 = |
25 |
mm |
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l2 = |
58.75 |
mm |
> |
80 |
mm |
gwoździe nie mogą być wbijane w jednej osi |
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t2 = |
80 |
mm |
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= |
14.8141314116885 |
Mpa |
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= |
1296.23649852275 |
N |
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4147.95679527279 |
N |
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1383 |
N |
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4250.66359263647 |
Nmm |
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1578.81314807042 |
N |
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646.836193182045 |
N |
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730.311550119691 |
N |
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647 |
N |
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n= |
15.3 |
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toteż przyjęto |
16 |
gwoździ z każdej strony styku oraz z każdej steony elementu. |
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Rozmieszczenie gwoździ |
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(5+5*cosα)*d= |
35 |
mm |
|
- rozstaw wzdłuż włókien |
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5 * d = |
17.5 |
mm |
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- rozstaw prostopadły do włókien |
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5 * d = |
17.5 |
mm |
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- odl. od krawędzi nieobc. prostop. do włukien |
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prz. |
20 |
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(5+5*sinα)*d= |
18.2 |
mm |
|
- odl.od krawędzi obc. prostop. do włókien |
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prz. |
20 |
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10*d = |
35 |
mm |
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- odl. od końca nieobc. wzdł. Włókien |
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prz. |
40 |
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(10 + 5 * cosα)*d= |
|
52.5 |
mm |
- odl.od końca odc. wzdł. Włókien |
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prz. |
60 |
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Liczba szeregów gwoździ w pasie |
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|
6.28571428571429 |
|
przyjęto |
7 |
szeregi co |
|
20 |
mm |
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Liczba rzędów gwoździ w pasie |
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4.57142857142857 |
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Długość nakładek |
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480 |
mm |
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II Stan graniczny użytkowalności |
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(Ugięcie dźwigara kratowego) |
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Ugięcie od obciążeń stałych |
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Obciążenie charakterystyczne w węzłach układu |
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4.153 |
kN |
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2.454 |
kN |
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Pręty |
Długość |
Pole |
Ni1 |
Nik' [N] |
Ni2 |
Nik'' [N] |
Nik= |
U inst |
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przek |
P1=1 |
4.153 |
P2=1 |
2.454 |
Nik'+Nik'' |
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G1 |
4357 |
15200 |
-2.7 |
-11214 |
-1.8 |
-4417 |
-15631 |
0.6721 |
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G2 |
4357 |
15200 |
-2.13 |
-8847 |
-1.8 |
-4417 |
-13264 |
0.5703 |
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G1' |
4357 |
15200 |
-2.7 |
-11214 |
-1.8 |
-4417 |
-15631 |
0.6721 |
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G2' |
4357 |
15200 |
-2.13 |
-8847 |
-1.8 |
-4417 |
-13264 |
0.5703 |
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D1 |
5236 |
12000 |
2.24 |
9304 |
1.5 |
3681 |
12985 |
0.7082 |
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D2 |
4028 |
12000 |
1.49 |
6189 |
1.07 |
2626 |
8814 |
0.2638 |
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D1' |
5236 |
12000 |
2.24 |
9304 |
1.5 |
3681 |
12985 |
0.7082 |
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K1 |
2904 |
5600 |
-0.84 |
-3489 |
0 |
0 |
-3489 |
0.0000 |
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K1' |
2904 |
5600 |
-0.84 |
-3489 |
0 |
0 |
-3489 |
0.0000 |
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K2 |
5236 |
5600 |
0.75 |
3115 |
1.1 |
2699 |
5814 |
0.4984 |
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K2' |
5236 |
5600 |
0.75 |
3115 |
1.1 |
2699 |
5814 |
0.4984 |
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Σ = |
5.1616 |
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U inst = 0,5 * Σ = |
|
|
2.58081424469992 |
mm |
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2.58081424469992 |
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4.12930279151988 |
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od śniegu |
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Pręty |
Długość |
Pole |
Ni1 |
Nik' [N] |
Ni1od P2 |
u |
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przek |
P1=1 |
4.119 |
P2=1 |
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G1 |
4357 |
15200 |
-2.7 |
-11123 |
-1.8 |
0.410 |
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G2 |
4357 |
15200 |
-2.13 |
-8774 |
-1.8 |
0.323 |
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G1' |
4357 |
15200 |
-2.7 |
-11123 |
-1.8 |
0.410 |
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G2' |
4357 |
15200 |
-2.13 |
-8774 |
-1.8 |
0.323 |
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D1 |
5236 |
12000 |
2.24 |
9228 |
1.5 |
0.431 |
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D2 |
4028 |
12000 |
1.49 |
6138 |
1.07 |
0.157 |
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D1' |
5236 |
12000 |
2.24 |
9228 |
1.5 |
0.431 |
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K1 |
2904 |
5600 |
-0.84 |
-3460 |
0 |
0.000 |
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K1' |
2904 |
5600 |
-0.84 |
-3460 |
0 |
0.000 |
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K2 |
5236 |
5600 |
0.75 |
3090 |
1.1 |
0.227 |
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K2' |
5236 |
5600 |
0.75 |
3090 |
1.1 |
0.227 |
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Σ = |
2.9407 |
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U inst = 0,5 * Σ = |
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1.47034546296682 |
mm |
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1.47034546296682 |
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1.83793182870852 |
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od wiatru |
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sprawdz czy te wartości są właściwe dobrane |
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Pręty |
Długość |
Pole |
Ni1 |
Nik(W) od |
Ni1 od |
Nik(W) od |
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Ni2 |
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przek |
W1=1 |
Wn1k= |
0.905 |
W2=-1 |
Wo2k= |
-1.19 |
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P2=1 |
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G1 |
4357 |
15200 |
-1.18 |
-1068.08 |
-1.08 |
1280.58 |
212 |
-1.8 |
-0.008 |
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G2 |
4357 |
15200 |
-1.18 |
-1068.08 |
-1.08 |
1280.58 |
212 |
-1.8 |
-0.008 |
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G1' |
4357 |
15200 |
-1.08 |
-977.57 |
-1.18 |
1399.15 |
422 |
-1.8 |
-0.016 |
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G2' |
4357 |
15200 |
-1.08 |
-977.57 |
-1.18 |
1399.15 |
422 |
-1.8 |
-0.016 |
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D1 |
5236 |
12000 |
0.7 |
633.61 |
0.9 |
-1067.15 |
-434 |
1.5 |
-0.020 |
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D2 |
4028 |
12000 |
-0.2 |
-181.03 |
0.9 |
-1067.15 |
-1248 |
1.07 |
-0.032 |
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D1' |
5236 |
12000 |
-0.2 |
-181.03 |
1.8 |
-2134.30 |
-2315 |
1.5 |
-0.108 |
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K1 |
4357 |
5600 |
-1 |
-905.15 |
0 |
0.00 |
-905 |
0 |
0.000 |
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K1' |
4357 |
5600 |
0 |
0.00 |
-1 |
1185.72 |
1186 |
0 |
0.000 |
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K2 |
4357 |
5600 |
0.9 |
814.64 |
0 |
0.00 |
815 |
1.1 |
0.050 |
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K2' |
4357 |
5600 |
0 |
0.00 |
0.9 |
-1067.15 |
-1067 |
1.1 |
-0.065 |
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Σ = |
-0.223 |
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U inst = 0,5 * Σ = |
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|
-0.111350948420241 |
mm |
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-0.111350948420241 |
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Udop = |
|
24.1666666666667 |
mm |
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Ufin= |
|
5.97 |
mm |
|
bez obciążenia wiatrem gdyż daje ono ugięcie odwrotne |
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5.97 |
< |
24.1666666666667 |
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warunek spełniony |
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