2.1
Dane: Szukane: Wzory:
m =
t = 3 h m = k Å" I Å"t
I = 5 A
kAg = 1,118 mg / C
t = 3Å"3600 = 10800 s
m = k Å" I Å"t = 1,118Å"5Å"10800 = 60372 mg = 60,372 g
______________________________________________________________________
2.2
Dane: Szukane: Wzory:
t = 50 min m = k Å" I Å"t
kCu =
m1 = 70 g
m2 = 73,96 g
I = 4 A
t = 50Å"60 = 3000 s
m = m2 - m1 = 73,96 - 70 = 3,96
m = k Å" I Å"t
m 3,96
k = = = 0,00033 g / AÅ" s = 0,33 mg / C
I Å"t 4Å"3000
______________________________________________________________________
2.3
Dane: Szukane: Wzory:
m = 10 kg W = m = k Å" I Å"t
W = P Å"t
U = 4V
U = I Å" R
kCu = 0,3294 mg / C
m = 10 kg = 10000000 mg
m = k Å" I Å"t
m 10000000
I Å"t = =
k 0,3294
P = U Å" I
10000000
W = P Å"t = U Å" I Å"t = 4Å" = 121432908W Å" s = 33,7 kWh
0,3294
______________________________________________________________________
2.4
Dane: Szukane: Wzory:
m = 2 T t = m = k Å" I Å"t
I = 10000 A = 104 A
kAl = 0,0932 mg / C
m = 2 T = 2Å"109 mg
m = k Å" I Å"t
m 2Å"109
t = = = 21, 459Å"105 s = 596 h
I Å" k 104 Å"0,0932
______________________________________________________________________
2.5
Dane: Szukane: Wzory:
t = m = k Å" I Å"t
S =1 m2
h = 0,2 mm = 0, 2Å"10-3 m
I = 30 A
kAl = 0,3294 mg / C
´Cu = 8,9Å"103 kg / m3
V =1Å"0,2Å"10-3 = 0,2Å"10-3 m3
m = V Å"´Cu = 0, 2Å"10-3 Å"8,9Å"103 =1,78 kg =1,78Å"106 mg
m = k Å" I Å"t
m 1,78Å"106
t = = = 0,1801Å"106 s = 50 h
I Å"k 30Å"0,3294
______________________________________________________________________
2.6
Dane: Szukane: Wzory:
t = m = k Å" I Å"t
V = 0,5 m Å" 0,1 m Å"10 mm
I = 50 A
kAl = 0,3294 mg / C
´Cu = 8,9Å"103 kg / m3
· = 90%
V = 0,5 m Å" 0,1 m Å"10 mm = 0,5 m Å" 0,1 m Å" 0,01 m = 0,5Å"0,1Å" 0,01 = 0,5 Å"10-3 m3
m = V Å"´Cu = 0,5 Å"10-3 Å"8,9Å"103 = 4, 45 kg = 4,45Å"106 mg
tylko część dostarczonej energii jest użytkowa
Io
· =
I
Io =· Å" I = 90% Å"50 = 45 A
m = k Å" Io Å"t
m 4, 45Å"106
t = = = 0,3002Å"106 s = 83, 4 h
Io Å"k 45Å"0,3294
______________________________________________________________________
2.7
Dane: Szukane: Wzory:
h = m = k Å" I Å"t
Sp = 0,4 dm2
n = 3
J = 20 A / m2
t = 3 h
kAg = 1,118 mg / C
´Ag =10,5Å"103 kg / m3
S = n Å" Sp = 3Å"0, 4 dm2 = 1, 20 dm2 = 1, 2 Å"10-2 m2
I = J Å" S = 20Å"1, 2 Å"10-2 = 0, 24 A
t = 3 h = 3Å"3600 = 10800 s
m = kAg Å" I Å"t = 1,118Å"0, 24Å"10800 = 2897 mg = 2,897 Å"10-3 kg
m 2,897 Å"10-3
V = = = 0, 276Å"10-6 m3
´Ag 10,5Å"103
V 0, 276Å"10-6
h = = = 0,23Å"10-4 m = 0,023 mm
S 1, 2 Å"10-2
m = k Å" Io Å"t
m 4, 45Å"106
t = = = 0,3002Å"106 s = 83, 4 h
Io Å" k 45Å"0,3294
______________________________________________________________________
2.8
Dane: Szukane: Wzory:
D = 5 cm t = m = k Å" I Å"t
m = V Å"´
b = 0,02 mm
I = 0, 4 A
kAg = 1,118 mg / C
´Ag = 10,5Å"103 kg / m3
D 5
r = = = 2,5 cm = 2,5Å"10-2 m
2 2
b = 0,02 mm = 2Å"10-5 m
3
4 4 3 4
V = V2 -V1 = Ä„ Å"(r + b)3 - Ä„ Å" r = Å"3,14Å"[(2,5Å"10-2 + 2Å"10-5)3 - 2,5Å"10-2 ]
( )
( )
3 3 3
3
V = 4,187 Å"[(2500Å"10-5 + 2Å"10-5)3 - 2,5Å"10-2 ] = 4,187 Å"(15,6625Å"10-6 -15,625Å"10-6)
( )
V = 4,187 Å"0,0375Å"10-6 = 0,157 Å"10-6 m3
m = V Å"´Ag = 0,157 Å"10-6 Å"10,5Å"103 = 1,648Å"10-3 kg = 1,648Å"103 mg
m 1,648Å"103
t = = = 3686 s H" 61 min
kAg Å" I 1,118Å"0, 4
______________________________________________________________________
2.9
Dane: Szukane: Wzory:
m = 1 g m = k Å" I Å"t
mCl =
kH = 0,01045 mg / C
kCl = 0,3674 mg / C
mH = kH Å" I Å"t
mH
I Å"t =
kH
mCl = kCl Å" I Å"t
mCl
I Å"t =
kCl
mH mCl
=
kH kCl
mH 1
mCl = Å" kCl = Å"0,3674 = 35,15 g
kH 0,01045
______________________________________________________________________
2.10
Dane: Szukane: Wzory:
mAg =180 mg m = k Å" I Å"t
mCu =
kAg = 1,118 mg / C
kCu = 0,3294 mg / C
mAg = kAg Å" I Å"t
mAg
I =
kAg Å"t
mCu = kCu Å" I Å"t
mCu
I =
kCu Å"t
mAg mCu
=
kAg Å"t kCu Å"t
mAg
180
mCu = Å"kCu = Å"0,3294 = 53,03 mg
kAg 1,118
______________________________________________________________________
2.11
Dane: Szukane: Wzory:
Q = m = k Å" I Å"t
mH = 1,008 g = 1008 mg
Q = I Å"t
kH = 0,01045 mg / C
Q = I Å"t
mH = kH Å" I Å"t
mH = kH Å"Q
mH 1008
Q = = = 96450 C
kH 0,01045
______________________________________________________________________
2.12
Dane: Szukane: Wzory:
m = k Å" I Å"t
I = 300 A m = V Å"´
g
=
kH = 0,01045 mg / C h
m3
´H = 0,08987 g / dm3
=
h
mH kH Å" I Å"t mg mg
îÅ‚ Å‚Å‚
= = 0,01045[ ]Å"300[A] = 0,01045 Å"300[A]
ïÅ‚ śł
t t C AÅ" s
ðÅ‚ ûÅ‚
mH mg g g
îÅ‚ Å‚Å‚ îÅ‚ Å‚Å‚
= 0,01045 Å"300 = 3,135Å"10-3 Å"3600 =11,3îÅ‚ Å‚Å‚
ïÅ‚ śł ïÅ‚ śł ïÅ‚ śł
t s h h
ðÅ‚ ûÅ‚ ðÅ‚ ûÅ‚ ðÅ‚ ûÅ‚
m kH Å" I Å"t
mg mg
îÅ‚ Å‚Å‚
0,01045îÅ‚ Å‚Å‚ Å"300[A] 0,01045 Å"300[A]
ïÅ‚ śł ïÅ‚ śł
V ´H ´H kH Å" I
C AÅ" s
ðÅ‚ ûÅ‚ ðÅ‚ ûÅ‚
= = = = =
g g
t t t ´H îÅ‚ Å‚Å‚
0,08987 0,08987Å"103 îÅ‚ 3 Å‚Å‚
ïÅ‚ śł ïÅ‚m śł
dm3
ðÅ‚ ûÅ‚ ðÅ‚ ûÅ‚
g
3,135Å"10-3 îÅ‚ Å‚Å‚
ïÅ‚ śł
V îÅ‚ Å‚Å‚ îÅ‚ Å‚Å‚
m3 m3
s
ðÅ‚ ûÅ‚
= = 0,03488Å"10-3 ïÅ‚ śł = 0,03488Å"10-3 Å"3600
ïÅ‚ śł
g
t îÅ‚ Å‚Å‚ s h
ðÅ‚ ûÅ‚ ðÅ‚ ûÅ‚
89,87
ïÅ‚ śł
m3
ðÅ‚ ûÅ‚
V îÅ‚ Å‚Å‚
m3
= 0,126
ïÅ‚ śł
t h
ðÅ‚ ûÅ‚
_____________________________________________________________________
2.13
Dane: Szukane: Wzory:
t = m = k Å" I Å"t
h =12 µm =12Å"10-6 m
m = V Å"´
J =1,8 A / dm2 =1,8Å"102 A / m2
I
J =
· = 95%
S
kNi = 0,304 mg / C
´Ni = 8,8Å"103 kg / m3 = 8,8Å"109 mg / m3
ilość prądu dostarczonego
I
J =
S
I = J Å" S
z różnych powodów tylko część Io prądu płynącego jest użytkowa i w czasie elektrolizy
nanosi Nikiel
Io
· =
I
V = S Å" h
m = V Å"´
m V Å"´ S Å" h Å"´ S Å" h Å"´ h Å"´
t = = = = =
kNi Å" Io kNi Å"· Å" I kNi Å"· Å" I kNi Å"· Å" J Å" S kNi Å"· Å" J
12Å"10-6 Å"8,8Å"109 105,6Å"103
t = = = 2030,3 s = 0,564 h
0,304Å"0,95Å"1,8Å"102 0,5201Å"102
______________________________________________________________________
2.14
Dane: Szukane: Wzory:
m = k Å" I Å"t
kFe =
b = 0,1 mm =1Å"10-4 m
m = V Å"´
J = 5000 A / m2
I
J =
t =10 min = 600 s = 6Å"102 s
S
· = 88,6%
´Fe = 7,7Å"103 kg / m3 = 7,7Å"109 mg / m3
ilość prądu dostarczonego
I
J =
S
I = J Å" S
z różnych powodów tylko część Io prądu płynącego jest użytkowa i w czasie
elektrolitycznego polerowania działa na stal.
Io
· =
I
V = S Å" h
m = V Å"´
m V Å"´ S Å"b Å"´ S Å"b Å"´ b Å"´
kFe = = = = =
t Å" Io t Å"· Å" I t Å"· Å" I t Å"· Å" J Å" S t Å"· Å" J
1Å"10-4 Å"7,7 Å"109 7,7 Å"105
kFe = = = 0, 2897 mg / C
6Å"102 Å"0,886Å"5Å"103 26,58Å"105
______________________________________________________________________
2.15
Dane: Szukane: Wzory:
m = k Å" I Å"t
I =
m = 1, 2 kg = 1, 2Å"106 mg
m = V Å"´
t = 8 h = 8Å"3600 s = 288Å"102 s
I
J =
kNi = 0,304 mg / C
S
m
I =
t Å" kNi
1, 2Å"106 1, 2Å"106
I = = = 137 A
288Å"102 Å"0,304 87,55Å"102
_____________________________________________________________________
2.16
Dane: Szukane: Wzory:
m =
v = 0,1 m / s m = k Å" I Å"t
m = V Å"´
I =
a = 60 cm = 0,6 m
I
J =
h = 0,002 mm = 2Å"10-6 m
S
t = 8 h = 8Å"3600 s = 288Å"102 s
kSn = 0,6149 mg / C
´Sn = 8,8Å"103 kg / m3
· = 90%
s = v Å"t
S = 2Å" s Å" a ponieważ cynuje siÄ™ dwie strony
S = 2Å"v Å"t Å" a
V = S Å" h = 2Å"v Å"t Å" a Å" h
m = ´ Å"V = ´ Å" 2Å"v Å"t Å" a Å" h = 8,8Å"103 Å" 2Å"0,1Å" 288Å"102 Å"0,6Å" 2Å"10-6 = 60,8 kg = 60,8Å"106 mg
Z ilość prądu dostarczonego z różnych powodów tylko część Io prądu płynącego jest
użytkowa i powoduje nakładanie cyny
Io
· =
I
Io =· Å" I
m
Io =
t Å" kSn
m
· Å" I =
t Å" kSn
m
I =
· Å"t Å" kSn
60,8Å"106
I = = 3815 A
0,9Å" 288Å"102 Å"0,6149
______________________________________________________________________