Report 8


  1. Introduction

During the experiment I examined the formation of stress concentration, near the hole in the plate, that was under the load P.

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We know that in case of irregularity of shape (places where cross-section area changes) one observes local concentration of stress. Such places (i.e. holes, threads) are so-called notches.

The local increase of stress, caused by notch, contributes to the drop of fatigue strength. The measure of the increase in strength is the shape factor αk:

αkmaxn

where: σmax - maximal stress in the area of stress concentr.

σn - nominal stress, calculated for the same are with the use of typical strength formulae, which don't take stress concentration into account

The aim of experiment was to:

Measure stress in notch area (hole in the plate) an determine shape factor αk based on measurement results.

  1. Description of experimental stand.

Experimental stand consists of plate with the hole in the center. The load is realized by the central force put near the edge of the hole, and 4 forces in the corners, all acting in the opposite direction to the central one. In this way the plate is buckled.

Those 4 forces are passed on to the other side, where the slats are.

We observe stress changes (interference fringes, called the isochromatic lines) in the polariscope.

    1. 0x08 graphic
      Scheme of forces acting in the system.

P - main load

P1,P2 - reaction forces

a, b, x - distances needed to

calculate moments of forces

    1. Scheme of plate and slat

  1. Equilibrium equations based on the upper schemes.

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0x08 graphic

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  1. Calculation of nominal stress.

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In order to find nominal stress I am going to use so-called “cylinder bending model”. In this method the plate bending is approximated by normal beam bending:

To find force Pw, length c (momentum arm),

and other data needed to find nominal stress we use the following equations:

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0x01 graphic

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0x01 graphic

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bending moment

0x08 graphic
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strength

Pw=P/2

Where:

k - length of plate

d - diameter of hole

δ - thickness of the plate

k/cosα - length of the A-A intersection line

Finally: 0x01 graphic

W=1.1712·10-6 m3

  1. Obtained data.

Ni

1

1.5

2

2.5

4

dz

52

79

96

107

130

  1. Calculations and juxtaposition of results.

    1. Loading force P in Newtons

As we know that 1dz=3.23kG it is easy to calculate force P in Newtons.

P[N] = dz·3.23kg·9.81 m/s2

    1. Linear regression function - N and Nkor

Then, with the usage of formulas for linear regression:

0x01 graphic

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Thus we find the functions:

0x01 graphic

Nkor=a1P

    1. Normal stress

To find normal stress σ1 we use the equation:

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, where:

C- coefficient of correction (1.25 in that case)

E - Young modulus for Alloy steel (7·104 MN/m2)

ν  Poisson ratio for alloy (0.32)

f  model constant (0.00128)

    1. Error of normal stress

To calculate error of normal stress calculation we use the following formulae:

0x01 graphic

    1. Obtained results

Ni

1

1,5

2

2,5

3

P[N]

1647,6876

2503,218

3041,885

3390,434

4119,219

Ni-N

0,087747769

-0,13209

-0,08531

0,121421

0,00823

Nkor

1,386345195

2,106178

2,559407

2,852672

3,465863

σ1 [MN/m2]

75,27854411

114,3655

138,9758

154,9001

188,19636

δσ1 [MN/m2]

134,2

134,4

134,5

134,7

134,9

σn [MN/m2]

47159282,94

71645834

87063292

97039294

117898207

0x01 graphic

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    1. Shape factor

P[N]

1647,6876

2503,218

3041,885

3390,434

4119,219

αk

1,199551742

1,184368

1,299514

1,457399

1,4394621

So the mean value of shape factor is: αk = 1,316059

    1. Derivation of error analysis formulae.

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  1. Remarks, comments and conclusions.

To sum up, we can say that our experiment was successful. From the data we obtained during the exercise, we fulfilled our aim and expectations.

We can conclude that:

We can also notice, that the method we used is relatively simple and efficient.

Experiment no. 8 - Stress concentrations in machine elements

Page - 2 -

coefficient



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