Lp.	l1	l3	l3 – l1	λśr ± u(λśr)	T±(u(T))	vT ±(u(vT))	f ± u(f)	fgen.
	[m]	[m]	[m]	[m]	[ K ]	[ m/s ]	[ Hz ]	[ Hz ]
1.	0,103	0,512	0,409	0,411±0,002	293±0,58	332,71±0,36	809,51±	800,1±5
2.	0,104	0,519	0,415
3.	0,101	0,509	0,408
4.	0,106	0,524	0,418
5.	0,103	0,513	0,41
6.	0,102	0,51	0,408
7.	0,101	0,512	0,411
8.	0,1	0,508	0,408
9.	0,105	0,519	0,414
10.	0,102	0,511	0,409

III. Obliczenia i rachunek błędu

a) obliczenia

T=293K

V_T=V₀$\sqrt{1 + 0,004(T - T_{0}})$

V_T=$331,4\sqrt{1 + 0,0004(293 - 273,16}$) ≅ 332,71[m/s]

λ_sr=$\frac{1}{n}\sum_{k = 1}^{n}\lambda_{k}$=$\frac{\lambda_{1 +}\lambda_{2 +}\lambda_{10}}{10} \cong$ 0,411[m]

f=$\frac{V_{T}}{\lambda}$=$\frac{332,71}{0,411} \cong$ 809,51[Hz]

b) rachunek błędu

Przyjęto

ΔT=1

Δl=0,01[m]

u(λ_śr)=$\sqrt{\frac{\sum_{k = 1}^{10}{(\lambda_{k -}\lambda_{sr})^{2}}}{n(n - 1)}}\ \cong$ 0,002[m]

u(T)=$\frac{wartosc\ dzialki\ elementarnej}{\sqrt{3}}\ $= $\frac{1}{\sqrt{3}} \cong$0,58

u(v_T)=$\left\lbrack \frac{\partial V_{T}}{\partial T} \right\rbrack$*u(T)=$\left\lbrack \frac{V_{T}*\frac{1}{2}*0,004}{1 + 0,004({T - T}_{0})} \right\rbrack$*u(T)=$\left\lbrack \frac{331,4*\frac{1}{2}*0,004}{1 + 0,004*19,84} \right\rbrack$*0,58≅0,36$\frac{m}{s}$

u(f)=$\sqrt{\left( \frac{\partial f}{\partial\lambda} \right)^{2}*u(\lambda)^{2} + \left( \frac{\partial f}{\partial V_{T}} \right)*u(V_{T})^{2}} =$

$= \sqrt{\left( \frac{V_{T}}{\lambda^{2}} \right)^{2}*u(\lambda)^{2} + \frac{1}{\lambda^{2}}*u(V_{T})^{2}}$=$\sqrt{\left( \frac{332,71}{{0,411}^{2}} \right)^{2}*0,002 + \frac{1}{{0,411}^{2}}*0,36^{2}} \cong$2,14[Hz]