b) X=-511/512 Y=19/32

1* (1.111111111)zm (0.100110)zm

.111111111

-.100110000 w=0 bity znakowe są różne, więc odejmowanie

1.011001111zm

2* (1.0000000000)zu1 (0.10011)zu1

1.000000000

+0.10011

1.100110000zu1

3* (1.000000001)zu2 (0.10011)zu2

1.000000001

+0.10011

1.100110001

3. a) X=27/32 Y=-3/4

(0.11011)zm * (1.10101)zm = (1.1000110111)zm

11011

*10101

11011

00000

11011

00000

+11011

1000110111

b) X=-3/4 Y=7/8

(1.11)zm * (0.111)zm = (1.10101)zm

111

*011

111

+111

10101

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