Sprawozdanie nr 3a
Logika układów cyfrowych
Prow. A. Sterna
Zadanie 1
Układ synchroniczny o zadanej liczbie stanów
1412108642013579111315
Przy przesunięciu czasowym JK następuje:
00 0 -
01 1 -
10 - 1
11 - 0
Tabela prawdy:
T T+1
|
Q2 |
Q3 |
|
Q1 |
Q2 |
Q3 |
Q4 |
J1 |
K1 |
J2 |
K2 |
J3 |
K3 |
J4 |
K4 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
1 |
0 |
- |
0 |
- |
0 |
- |
1 |
- |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
1 |
0 |
- |
0 |
- |
1 |
- |
- |
0 |
0 |
0 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
- |
0 |
- |
- |
1 |
0 |
- |
0 |
0 |
1 |
1 |
0 |
1 |
0 |
1 |
0 |
- |
1 |
- |
- |
1 |
- |
0 |
0 |
1 |
0 |
0 |
0 |
0 |
1 |
0 |
0 |
- |
- |
1 |
1 |
- |
0 |
- |
0 |
1 |
0 |
1 |
0 |
1 |
1 |
1 |
0 |
- |
- |
0 |
1 |
- |
- |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
0 |
0 |
- |
- |
0 |
- |
1 |
0 |
- |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
- |
- |
1 |
- |
1 |
- |
0 |
1 |
0 |
0 |
0 |
0 |
1 |
1 |
0 |
- |
1 |
1 |
- |
1 |
- |
0 |
- |
1 |
0 |
0 |
1 |
1 |
0 |
1 |
1 |
- |
0 |
0 |
- |
1 |
- |
- |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
0 |
0 |
- |
0 |
0 |
- |
- |
1 |
0 |
- |
1 |
0 |
1 |
1 |
1 |
1 |
0 |
1 |
- |
0 |
1 |
- |
- |
1 |
- |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
0 |
- |
0 |
- |
1 |
1 |
- |
0 |
- |
1 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
- |
0 |
- |
0 |
1 |
- |
- |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
0 |
0 |
- |
0 |
- |
0 |
- |
1 |
0 |
- |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
- |
0 |
- |
0 |
- |
0 |
- |
1 |
Siatki Karnough'a dla każdego J i K:
Q1Q2 Q3Q4 |
00 |
01 |
11 |
10 |
00 |
0 |
0 |
- |
- |
01 |
|
0 |
- |
- |
11 |
0 |
1 |
- |
- |
10 |
0 |
0 |
- |
- |
Q1Q2
|
00 |
01 |
|
10 |
00 |
- |
- |
0 |
1 |
01 |
- |
- |
0 |
0 |
11 |
- |
- |
0 |
0 |
10 |
- |
- |
0 |
0 |
Q1Q2 Q3Q4 |
00 |
|
11 |
10 |
00 |
0 |
- |
- |
1 |
|
0 |
- |
- |
0 |
11 |
1 |
- |
- |
1 |
10 |
0 |
- |
- |
0 |
Q1Q2 Q3Q4 |
|
01 |
11 |
10 |
00 |
- |
1 |
1 |
- |
01 |
|
0 |
0 |
- |
11 |
- |
1 |
0 |
- |
10 |
- |
0 |
0 |
- |
Q1Q2
|
|
01 |
11 |
|
00 |
- |
- |
- |
- |
01 |
- |
- |
- |
- |
11 |
|
1 |
0 |
1 |
10 |
1 |
1 |
1 |
1 |
Q1Q2 Q3Q4 |
00 |
|
11 |
10 |
00 |
|
1 |
1 |
1 |
01 |
1 |
1 |
- |
1 |
11 |
- |
- |
- |
- |
10 |
- |
- |
- |
- |
Q1Q2
|
00 |
01 |
11 |
10 |
00 |
1 |
0 |
0 |
0 |
01 |
- |
- |
- |
- |
11 |
- |
- |
- |
- |
10 |
0 |
0 |
0 |
0 |
Q1Q2 Q3Q4 |
00 |
01 |
11 |
10 |
00 |
- |
- |
- |
- |
01 |
0 |
|
0 |
0 |
11 |
0 |
0 |
1 |
0 |
10 |
- |
- |
- |
- |
Równania z siatek:
Przekształcenia równań:
Schemat:
K4
J4
J3
K3
J2
K2
J2
J1
K1