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iol: KH₂PQ₁ -> K* + H.PO,-

^“F^P0₄-₊ H₂0 <=> H₃P0₄ + OH-, K_h3 = K_w/<! = 10¹⁴/1,110²

H₂P0₄- H* + HP0₄²-, K₂ = 1,2 10-⁷ HP0₄²- <=> H⁺ + P0₄³', K₃ = 1.8 10¹²

Równania:

K, = [H₃P0₄][OH ]/[H₂P0₄ ], p = [H₃P0₄]/ c₀,_H2P04.

K₂ = [HP0₄² ][H* ]/[H₂P0₄], a = [HP0₄² ]/ C_oh2po4.

K₃ = [P0₄³-][H- ]/[HP0₄² ], a- ([P0₄³ ]/([P0₄³ > [HPO,²-]) Kw = [OH-][H*]

0),H2PO4- - [H₃P0₄] + [H₂P0₄ ] + [HP0₄²-] ₊ [P0₄³-]

1[H₂P0₄ ] ₊ 2[HP0₄²-] ₊ 3[P0₄³ ] ₊ l[OH-] - 1[H-] + 1C₀,_H2P04.