ZESTAW G
ZESTAW D
Zad
Zad
El=l 2V. E2=10V. R1 =R2=2kll R3-03kQ. C=2pF cbwod otwaty l EII*Rl-!*R3-E2-0 E1-E2=1(RI*R3) 12-10=1(2*0.5)2=2.51 1=2' 2.5=0.8A otnrod /ai&iudy I EM*Rl-Uc-0 U-EI-I*RI-10.4 Wc=0i5CU!=0i5*2*l04*(ia4)l=104*l0s=ia‘ )
Obwód zankmęty II E2* I*R3-Uc Uc-€2*I*R3
Uc=l0'0.8*0.5”l0,4V t ■ R2*C
Zad.
uO)“I4I.4 <ai(314<ut*x 3). P-100W. I-1.25A MI*Ica*«p 100-100*1.25 cowp co«4>-10OI 25-08 <^37°
<pu-60' <i-230 Z-Ul-80
Z=«0(co»3T^łłai23 >80(08*j0.4)=«4 • j32 }>lZ“16t*ji2*64 -j3164-j32 =64j325120=0.0125-/) .00625 X=|/R*!/JXi R-l-0.0125-80 Xl-1'0,00625-160
l(l)=1.25*>2 «ai(3l4t*230) p(l)=100.125<os(62a*830)
Zad W oacgowyin potac/aim RIjC woltciniazc V|,V>,V> wdcazupt po 100 V wyznaczyć w*azana V.V,:.V:i dla kontunacji połać zen podanej w tablicy
EI-30Y. Ia2-2A. R-I0a 1R-80H n-cr*a-' utow-ay-o ow*o-Rx rx*r-sio IORx-8Rx*SR 2Rx-8R Rx-4R IM0Q lnl=El/Rx=30/4O=O.75A Owx=lRx 0=1/R lno=lnl*ljr2=2‘0.75=2.?5A Rz =40* 10 50=81) LY-lflo*Rz-22Y IR-LYR-2.2 P-U,*I,-i8.4W Zad.
Li> |
Z1 |
Z2 |
Z3 |
V |
VI2 |
V23 |
1 |
C |
L |
R |
100 |
0 |
141.4 |
: |
I. |
1. |
c |
100 |
200 |
0 |
3 |
L |
R |
c |
100 |
141.4 |
141.4 |
4 |
C |
L |
c |
100 |
0 |
0 |
5 |
L |
C |
L |
100 |
0 |
0 |
U=Ll‘L2*Li
<p-4S-4>, - -90” lil=IOOe^ 4K=-jlOO 122= 100^=) 100 Li-200
U23-L2-ia-3100* 100-•.20000-141,4 Zad.
Da* o>-l 00 R=2QQ L-20OinH U-2A Obliczyć uO). <0. P<0 XU-«oI-100*200* 10‘=20(1 Z-R*jXI. R*jXl.-20-j20 20»j20* 20-j20 / 20-jM -58000*8000 400'400-(l0*jl0>n UL=XI.*IL-2A*j20-j40 -» wohcin«n-0 K=Uc R=HO20=}2A
1=2* 2>A -» ampctaiaaz =V 2^2'=>8=2 8 A <jw=wrtgl=45° *=M5°
P-Re( L*1 )~>50(2*j2^*80,jSO-80W u(t)-40v2 wiOOOoO1^ i(l)=2>2 *y«(10Ot*45,:)
S^SO^SO-I13 p(l)“80*ll3co«(20a. 54°)
Zad. Metoda potencjałów węzłowych
R=5ft. I=2QA. f=50łlz
U=1*R=100V tyle w»kaZe miernik V
UX0- Vl/rŁM LinWcudr-->'Uir.T*|/2( j,’- dt. t,’ :<a*2wt dt>-=>Uir/2T (T/2-<«o»28-«-0>=>Uin:/4-ETO'2 Unr=2*U=200V U«=UnV>2=141.4 tyte wdcnze nuaiuk V,
ZESTAW F
Cofce**.' •*“ ".r-;
±
r
Daic P-5000W V-220V f-50lb co.*>1-0.7 P=U*Ilcoafl II— P/ co.ę.l‘U-5000 0.7*220-324A Y 1=11/11=32.4/ 220*0.147
G=YIco»4»1=0.147*0.7=0.1 Bl = -Yl«i»l=-0.0707 Occu<p2-Y2 Y2-0.10.9-0.ll *2-25,82°
Yl 1=1 Rl*l jXL2» 1 R5-jXC5*1-jX06 Y22-1 KXL4-XC4) * 1 R5 -jXC5♦ 1 -jXC6 X12=I R5-jXC5*l -JXC6 V11*VI-L12*V2-E1R1 .Qł>jXC6
B> • Y2.m «?2 -0.11 *0.436- -0.01796 B=B2-BI= - 0.04796 * 0.0707=0.02274 B w C C=B w =0.02274/ 314=7.2*10 T Zad
<>> <»>—i
u(t)=282.8 «n(3l4t*x'6). P-400W. I=2.5A
P=U*1 cm* cos*=40O500=08 *=37° *u=30° *.=-7° Z-U/I-80 Z-80(co*37°»jan-7°>-64*j9.75 l'-l Z-0.015*/),0023 Y=IR*I)XL R=l 0.015=66.7 XL=I 0.0023=435 i(t)=2.5\2«iii(3l4» - 7°)
p(t)-400-500ccu(628t* 3<P)