65598

Przedział: Oś xśa

L ^pix = Rax + N = O    N = -f?_Av = -(-69.370) = 69.37

E^pi_r =*Ay~T=0    T = ł?_Ar = -6276

£M_j0 = M_X -R_Ayx = 0 M_x=R_Ayx dla x = 0 Mx=o = 0

dla x = a M_{v a} = - 62,76N*l,lm = - 69.04 Nm

Y P,_% — N cos( 90⁰ +<p)+Tcos <p+ R_h cos a_H = O

N =69.37 N T = —62.76N M _x =-62.76x

— N sirup + T cosq>+R_Bcosa_R = 0    » (c)

YPj_y *■ N sin(90° +<p) + T sin<p+ R„ sina„ =O

N cos <p + T sin <p + R_B sin a_B-0 _^ (d)

L Af_i0 = —M _x + (R_b cos<x_h )asin<p + ( R_r sin a_H )a( 1-cos ę)=0

M_x = R_Ba(cosa_B sin<p+sina_B -sina_Bcosę>)

dla (0 = 0 M_x = R_Ba(0 + sina_B-sina_B) = 0    -► Af* = 0

dla fi) = 90°

M_x = R_Ba(cosa„ +sina_R — O) = —45 J95 • 1 ,l(cos60° +sin60° ) = —69,04Nm

z równań (c) i (d)

cos <p sin <p

— N sinq> + T cos<p = —R_Bcosa_B N cosę>+T sin<p = —R_B sin a _B

T(cos ^J <P+ sin * ę ) = R_B (-cos a_Bcos<p- sin a_B sin <p) dla fi) = 0, T=-R_Bcosa,_it T =—(—45.95)cos60° = 22,97N 0) = 90°, T =~R_h sina_B T = —{—45.95)sin 60° =3979N — N sirnp + Tcos<p = —R_Bcosa_B    —sin<p

cosq>

\ cos q>+T sin <p = -R_n sina_B

N (cos ² <p+ sin² <p)= R_b (cos a_B sin <fr- sin a_B cos <p)

N = R_b (cosa_B sin <p - sin a_B cos 9)

dla fi) = 0,    N m-R_r sin a_B = -(-45,95 )sin 60° = 3979N

dla (0 = 90°,    N = R_b cos a_B = -45,95 cos 60° = -22,97 N

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