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(*

The following is one way to solve ((A + B) x C) + (A - (D x C) + B).

This example shows how the accumulator and the stack accumulator are used in TL logie. *)

(*

LD C MUL(B ADD A

)

ADD (A SUB (B ADD( D MUL < )

Linę number *)

^f2 Load C into accumulator.

'2

’3

Push C onto accumulator stack. Load B anto accumulator.

ADD A to B; ioad into accumulator.

Pop value of accumulator stack; rauitipiy this value by the value in the accumulator; load into accumulator.

^r5 ^f 6 ' 7 ^r8

Push accumulator    value    onto    accumulator    stack.    Load    A    into    accumulator.

Push accumulator    value    onto    accumulator    stack.    Load    B    into    accumulator.

Push accumulator    value    onto    accumulator    stack.    Load    D    into    accumulator.

Multiply C by D;    load into accumulator.

'9 Pop value ot accumulator stack; add this value to the value in the ^f accumulator; load into accumulator.

)

'10 Pop value of accumulator stack; subtract this value from the value in the ^f <2CCŁ^wJ<2tor/ 2o.acf into accumulator.

)

^f 22 Pop value of accumulator stack; add this value to the value rn the ' accumulator; load into accumulator.

ST royDINT '12 Load value of accumulator into D1NT variable myDINT.