Obliczenia obiegu teoretycznego

1. Wła

ś

ciwo

ś

ci czynnika roboczego (powietrza)

ρ

1.09

kg

m

3

:=

g

ę

sto

ść

wilgotnego powietrza w temp. 50 st. C

R

287

J

kg K

⋅

:=

k

1.4

:=

cv

715

J

kg K

⋅

:=

cp

988

J

kg K

⋅

:=

M

V1 ρ

⋅

1.264

10

3

−

×

kg

=

:=

2. Obliczanie parametrów kolejnych punktów (obiegu Sabathe)

1.

p1

0.956bar

:=

V1 1159.8cm

3

≡

T1

333K

:=

2.

V2

60.09cm

3

:=

p2

p1

V1
V2













k

⋅

60.29 bar

⋅

=

:=

T2

p2 V2

⋅

M R

⋅

998.58 K

=

:=

3.

V3

V2 60.09 cm

3

⋅

=

:=

p3

70bar

:=

T3

p3 V3

⋅

M R

⋅

1.16

10

3

×

K

=

:=

4.

Qv

M cv

⋅

T3 T2

−

(

)

⋅

145.31 J

=

:=

Q

2169.838J

:=

Qp

Q

Qv

−

2.02

10

3

×

J

=

:=

T4

Qp

M cp

⋅

T3

+

2.78

10

3

×

K

=

:=

p4

70bar

:=

V4

M R

⋅

T4

⋅

p4

144.1 cm

3

⋅

=

:=

5.

V5

V1 1.16 10

3

×

cm

3

⋅

=

:=

p5

p4

V4
V5













k

⋅

3.78 bar

⋅

=

:=

T5

p5 V5

⋅

M R

⋅

1.21

10

3

×

K

=

:=

3. Obliczanie sprawno

ś

ci obiegu

Qodp

M cv

⋅

T5 T1

−

(

)

⋅

790.23 J

=

:=

Lt

Q

Qodp

−

1.38

10

3

×

J

⋅

=

:=

η

Lt

Q

63.6 %

⋅

=

:=