z
1800
1500
1500
2250
:=
wyznaczamy symbolicznie zw i zl
zw
z
0 0
,
z
0 1
,
z
1 0
,
⋅
z
1 1
,
zl
+
−
=
solve zl
,
2250
−
zw
800
−
(
)
zw
1800
−
(
)
⋅
→
zl
z
1 1
,
z
0 1
,
z
1 0
,
⋅
z
0 0
,
zw
+
−
=
solve zl
,
2250
800
zw
+
(
)
1800
zw
+
(
)
⋅
→
rozwiazanie uk. rownan z 2 nie wiadomymi:
2250
−
zw
800
−
(
)
zw
1800
−
(
)
⋅
2250
800
zw
+
(
)
1800
zw
+
(
)
⋅
=
solve zw
,
1200
1200
−
→
zw
1200
:=
zl
2250
800
zw
+
(
)
1800
zw
+
(
)
⋅
:=
zl
1500
=
Kp
P
L
P
dysp
=
Kp
E
2
zl
⋅
zl zw
+
(
)
2
E
2
4 zw
⋅
=
solve Kp
,
80
81
→